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olasank [31]
3 years ago
5

Write the point-slope form of each graph. Use the red point to write your equation. State the point and slope.

Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0
Answer:

First Graph:

Slope = - 4/5

Point-Slope Form: y - 3 = - 4/5 (x + 2)

Point: (-2, 3)

Second graph:

Slope = 4

Point-Slope Form: y + 6 = 4 (x + 1)

Point: (-1, -6)

Step-by-step explanation:

First graph has two points: (-2, 3) & (8, -5)

Use the two points to find the slope using the Slope-Formula

Slope-Formula: y2 - y1/x2 - x1

m = slope

m = - 5 - 3/8 - - 2

m = - 8/10

m = - 4/5

The slope of the line will be - 4/5

Now for Point-Slope Form, we’ll need to use the two points with the slope to identify the Point-Slope Form of the graph

Two points: (-2, 3) & (8, -5)

Slope: - 4/5

Point-Slope Formula: y - y1 = m (x - x1)

Point-Slope Form: y - 3 = - 4/5 (x + 2)

The point will be: (-2, 3)



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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
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Answer:

Considering the given equation y = log_{3}x\\

And the ordered pairs in the format (x, y)

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For (\frac{1}{3}, a_{0} )

x=\frac{1}{3}

y=a_{0}

y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1

So the ordered pair will be (\frac{1}{3}, -1 )

For (1, a_{1} )

x=1

y=a_{1}

y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0

So the ordered pair will be (1, 0 )

For (3, a_{2} )

x=3

y=a_{2}

y = log_{3}x\\y = log_{3}3\\y = 1

So the ordered pair will be (3, 1 )

For (9, a_{3} )

x=9

y=a_{3}

y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2

So the ordered pair will be (9, 2 )

For (27, a_{4} )

x=27

y=a_{4}

y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3

So the ordered pair will be (27, 3 )

For (81, a_{5} )

x=81

y=a_{5}

y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4

So the ordered pair will be (81, 4 )

4 0
4 years ago
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