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2 years ago

Error error error error

Mathematics

2 answers:

Eduardwww [97]2 years ago

8 0

Answer:

I really like helping people so can you take this app more seriously ..?

Step-by-step explanation:

maks197457 [2]2 years ago

5 0

Ummmmm i don’t know sorry

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A certain library assesses fines for overdue books as follows. on the first day that a book is overdue, the total fine is $0.10.

Volgvan

It the fourt day the total is 0.70 because
Day one: .10
Day two: you double it so .20
Day three: you double it again so .40
Day four: you add .30 so .70 is the total

3 0

2 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

2 years ago

Read 2 more answers

At a fundraiser, students sold chocolate bars with almonds and chocolate bars with walnuts. The number of chocolate bars with al

BabaBlast [244]

Answer:

Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

Step-by-step explanation:

Let number chocolate bars with almonds be x

Also let number chocolate bars with walnuts be y

Given:

Number of chocolate bars with almonds that were sold one weekend was 3 less than 2 times the number of chocolate bars with walnuts.

Framing the above sentence in equation form we get;

$x=2y -3$

Also given:

The number of chocolate bars with walnuts plus 4 times the number of chocolate bars with almonds was 300.

Framing the above sentence in equation form we get;

$4x+y=300$

Now Substituting the value of x in above equation we get;

$4x+y=300\\4(2y-3)+y=300\\8y-12+y=300\\9y=300+12\\9y=312\\\\y=\frac{312}{9} \approx 34.67$

Now we will substitute the value of y in equation $x=2y -3$ we get;

$x=2y-3 = 2\times34.67 -3 = 69.34-3\approx66.34$

Hence, Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

6 0

3 years ago

How much is 2/3 of 9 marbles?

Umnica [9.8K]

( 9 ÷ 3 ) x 2 = 3 x 2 = 6 marbles ;

4 0

2 years ago

A school holds classes from 8:00 A.M to 2:00 P.M. For what percent of 24-hour day does this school hold classes?

lesya [120]

Answer:

25%

Step-by-step explanation:

So first we need to find out how many hours the school has class. Its 4 hours from 8 to noon, then another 2 from noon to 2. This means the school has class 6 hours a day.

Now we need to figure out the percent. we need to have hours of school over total hours or 6/24

6/24

we can simplify this by dividing both sides by 6

(6/6)/(24/6)=1/4

1/4 is 25%

The school holds class for 25% of the day

5 0

3 years ago

Read 2 more answers