VvLabel Slope and Y-intercept in each Equation

2 answers:

5 0

Hey if this helps anyone who reads this if that is in standard form do the opposite of A over B reduce that if you can(that gets you your slope), and then do C over B and then divided that (that gets you your Y-intercept)

This way is so much faster and so much easier than the long way

Kamila [148]3 years ago

4 0

1- slope is 4 y intercept 0,2

2- slope is 6 y intercept 0,5

3- slope is 2 y intercept is 0,5

4 -slope is 1 y intercept is 0, 3/4

5- slope is 10 y intercept is 0,3

6- slope is 4 y intercept is 0,1/2

7- slope is 4 y intercept is 0, 3/2

8- slope is 1 y intercept is 0,2

You might be interested in

If a pair of perpendicular lines are rotated, which is true?

Rzqust [24]

The <em>correct answer</em> is:

D) Rotated perpendicular lines always remain perpendicular lines.

Explanation:

Perpendicular lines, by definition, meet at a 90° angle.

As long as both lines are rotated the same direction and the same angle, then the angle between the two lines will not change. They will continue to be perpendicular, no matter how many degrees or which direction they are rotated.

5 0

4 years ago

Read 2 more answers

How do you write three hundred six and four tenths in standard form?

jonny [76]

Answer:

364 I think.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

X+2/4=3/8 Solve for x pls!!

Oksana_A [137]

Answer:

x= $\frac{1}{2}$ or 0.5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2% of the population suffers from the terrible disease conditionitis. The test for conditionitis comes back positive 98% of the

vlabodo [156]

Answer:

8% probability that he or she actually has the disease

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?

This means that:

Event A: Test comes back positive.

Event B: Having the disease.

Test coming back positive:

2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that $P(A|B) = 0.98$