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2 years ago

Can someone please help me

Mathematics

1 answer:

leonid [27]2 years ago

5 0

Answer:

The answer is C. U=3x and V=2y^3

Step-by-step explanation:

3x*3x=9x^2

2y^3*-2y^3=-4y^6

Other variables cancel each other out

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A triangle has a base of 3 feet and an area of 15 square feet. Find the triangle's height

erik [133]

Answer:

10 ft

Step-by-step explanation:

The formula for the area of a triangle can be used. Put the known values into the formula and solve for the unknown.

A = (1/2)bh

15 = (1/2)(3)h

h = 15/1.5 = 10

The triangle's height is 10 feet.

6 0

3 years ago

Read 2 more answers

Customers arrive at a checkout counter in a department store according to a Poisson distribution at an average of seven per hour

jasenka [17]

Answer:

a) $P(X\leq 3) =0.0009119+0.00638+0.0223+0.0521=0.0818$

b) $P(X \geq 2) = 1-P(X$

c) $P(X=5) =\frac{e^{-7} 7^5}{5!}=0.128$

Step-by-step explanation:

Let X the random variable that represent the number of customers that arrive in a given hour. We know that $X \sim Poisson(\lambda)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this case we have $\lambda= 7 \frac{customers}{hour}$

Part a

No more than 3 means:

$P(X\leq 3) = P(X=0) +P(X=1) +P(X=2) +P(X=3)$

And if we find the individual probabilites we got:

$P(X=0) =\frac{e^{-7} 7^0}{0!}=0.0009119$

$P(X=1) =\frac{e^{-7} 7^1}{1!}=0.00638$

$P(X=2) =\frac{e^{-7} 7^2}{2!}=0.0223$

$P(X=3) =\frac{e^{-7} 7^3}{3!}=0.0521$

So then if we replace we got:

$P(X\leq 3) =0.0009119+0.00638+0.0223+0.0521=0.0818$

Part b

We want the probability that at least two so we can do this:

$P(X \geq 2) = 1-P(X$

The last step by the complement rule.

$P(X=0) =\frac{e^{-7} 7^0}{0!}=0.0009119$

$P(X=1) =\frac{e^{-7} 7^1}{1!}=0.00638$

$P(X \geq 2) = 1-P(X$

Part c

$P(X=5) =\frac{e^{-7} 7^5}{5!}=0.128$

6 0

3 years ago

Problem

Mrrafil [7]

Answer:

777

join my zoom meeting no audio no camera just chat

Step-by-step explanation:

Pass code: G0qkw3

ID: 448251

Numeric Passcode: 756933

8 0

4 years ago

Two satellites are orbiting Earth. The path of one satellite has the equation x^2 + y^2 = 56250000. The orbit of the other satel

ExtremeBDS [4]

Answer:

1,257 km

Step-by-step explanation:

The path of one satellite has the equation

$x^2 + y^2 = 56,250,000\\ \\x^2+y^2=7,500^2$

This is the equation of the circle with the center at the origin (Eartg) and the radius of 7,500 km.

The orbit of the other satellite is 200 km farther from the centre of Earth, so the radius of this orbit is 7,700 km.

Find the distances travelled by two satellites:

1st satellite:

$D_1=2\pi r_1=2\pi \cdot 7,500=15,000\pi \ km$

2nd satellite:

$D_2=2\pi r_2=2\pi \cdot 7,700=15,400\pi \ km$

Difference:

$D_2-D_1=15,400\pi -15,000\pi =400\pi \approx 1,257\ km$

6 0

4 years ago

HEY I KNOW YOU JUST SAW THAT COME BACK HERE AND CLICK AND HELP PLEASE

Nat2105 [25]

it might be -1 buttttt

4 0

3 years ago

Read 2 more answers