Given NL bisects KNM and KLM. Prove NKL equals NML

Myra reads 8 pages of her book. If this is 25% of her book. How many pages does she have left to read?

TiliK225 [7]

5 pages left in her book

5 0

3 years ago

What is the solution to this equation?

xxMikexx [17]

________________________________

Solution,

X+7=23

or,X=23-7

X=16 

The value of X is 16.

Hope it helps

Good luck on your assignment

______________________________

6 0

4 years ago

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5x=-y+6 solve for y when x =1,2,3

Assoli18 [71]

When x = 1
5(1) = -y + 6
5 = -y + 6
y = 6 - 5 = 1

When x = 2
5(2) = -y + 6
10 = -y + 6
y = 6 - 10 = -4

When x = 3
5(3) = -y + 6
15 = -y + 6
y = 6 - 15 = -9

6 0

3 years ago

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How to solve the polynomial 5x+3y+6x+9y

ANEK [815]

5x+3y+6x+9y

All you'd need to do is combine like terms. So add 5x to 6x and add 3y to 9y.

(5x+6x)+(3y+9y)

Final Answer: 11x + 12y

3 0

3 years ago

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What is the equation of a circle with center of (4,2) passing through the point (7,2)

attashe74 [19]

Answer:

(x-4)^2 + (y-2)^2 = 3^2

or

(x-4)^2 + (y-2)^2 = 9 (simplified if needed)

Step-by-step explanation:

-Equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$ where the center is (h, k) and the radius is $r^2$ .

-Place the center and the point onto that equation:

$(7-4)^2+(2-2)^2=r^2$

-Then, you solve:

$(7-4)^2+(2-2)^2=r^2$

$(3)^2+(0)^2=r^2$

$9 +0=r^2$

$9=r^2$

$\sqrt{9} =\sqrt{r^2}$

$3=r$

-So, the result is:

$(x-4)^2+(y-2)^2=3^2$

or

$(x-4)^2+(y-2)^2=9$ (simplified if needed)

3 0

3 years ago

￼Given NL bisects KNM and KLM. Prove NKL equals NML

Given NL bisects KNM and KLM. Prove NKL equals NML