All categories

3 years ago

Can someone help me with this. ^_^ THANKS

Mathematics

1 answer:

Fynjy0 [20]3 years ago

4 0

It would be B. because it's just 7 times 1.5

You might be interested in

ASAP WHATS THE ANSWER???

katrin [286]

Answer:

algebraic expression as they used variables

7 0

2 years ago

A is 60% of B , B is 30% of C, what percentage of C is A

zaharov [31]

A is 30% more than B. So, A = B + 30% of B = B + 30/100 *B = B + 3/10 *B = 13/10 *B. B is 60% less than C. So, B = C - 60% of C = C - 60/100 *C = C - 3/5 *C = 2/5 *C.

5 0

3 years ago

Y=-x^2 +78x-512 I need help with this problem

TiliK225 [7]

Answer:

Step-by-step explanation:

7 0

2 years ago

Pls help

Arturiano [62]

Answer:

Rule #4

Step-by-step explanation:

'Im' needs an apostrophe because it is a contraction I'm means I am

4 0

3 years ago

Read 2 more answers

A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%

andre [41]

Answer: a) 683 b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

$p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}$

a) Given : Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}}=\pm1.96$

Margin of error : $E=0.03$

Formula to calculate the sample size needed for interval estimate of population proportion :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683$

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.03})^2=1067.11111111\approx1067$

Hence, the required sample size would be 1067 .

3 0

2 years ago