Answer:
Need the other part of the problem
Step-by-step explanation:
Maybe...2(4+6)=2(10)
Step-by-step explanation:
<em>Check the attached file for solution and </em>
<em>simulation screen shot</em>
R-Code:
Sample mean
sd = 60 Population Standard deviation
n = 10 Sample size
conf.level = 0.99 Confidence level




<h3>
Answer: 1/38</h3>
This is because there's one space labeled "2" out of 38 spaces total.
This fraction is approximately equal to 1/38 = 0.0263 meaning there's roughly a 2.63% chance of landing on this space.