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3 years ago

7

This entire page about functions has me stuck, I know the basics of functions and graphs but i'm still a little stumped, please

help!!!!

1 answer:

attashe74 [19]3 years ago

7 0

Answer:

1. a 2.c

Step-by-step explanation:

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a marching band has 3 times as many trumpet players as tuba players how many trumpets players t, are there write and solve equat

Nina [5.8K]

Answer:

3 trumpet players

Step-by-step explanation:

t=1 and 3x1=3t

7 0

2 years ago

If the outliers are not included what is the mean of the data set, 79 79 80 82 50 78 83 79 81 82

White raven [17]

The mean to your question is 62.3
you need to add all of the numbers together and then divide by how many numbers are there to find the answer.

3 0

3 years ago

Pls,pls,pls,help me I will give lots of pound 100+ points

Bond [772]

Answer:

3log(10) -2log(5) ≈ 1.60206
no; rules of logs apply to any base. ln(x) ≈ 2.302585×log(x)
no; the given "property" is nonsense

Step-by-step explanation:

<h3>1.</h3>

The given expression expression can be simplified to ...

3log(10) -2log(5) = log(10^3) -log(5^2) = log(1000) -log(25)

= log(1000/25) = log(40) . . . . ≠ log(5)

≈ 1.60206

Or, it can be evaluated directly:

= 3(1) -2(0.69897) = 3 -1.39794

= 1.60206

__

<h3>2.</h3>

The properties of logarithms apply to logarithms of any base. Natural logs and common logs are related by the change of base formula ...

ln(x) = log(x)/log(e) ≈ 2.302585·log(x)

__

<h3>3.</h3>

The given "property" is nonsense. There is no simplification for the product of logs of the same base. There is no expansion for the log of a sum. The formula for the log of a power does apply:

$\log(a)\log(b)=\log(a^{\log(b)})=\log(b^{\log(a)})$

Numerical evaluation of Mr. Kim's expression would prove him wrong.

log(3)log(4) = (0.47712)(0.60206) = 0.28726

log(7) = 0.84510

0.28726 ≠ 0.84510

log(3)log(4) ≠ log(7)

4 0

2 years ago

Karman's Floral Shop has determined that the cost of production for one floral arrangement is $10.00. The shop charges $25.00 pe

Schach [20]

15 dollars because you subtract production cost from what is charged

4 0

3 years ago

Read 2 more answers

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

3 years ago