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Radda [10]
3 years ago
10

(c) Simplify 12x+y" (* x*')

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

12x + yx

= 12x + xy

= ans = xylem + 12x

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2x+14= -21-5x<br> Need to find out what x is but a step by step explanation please
adoni [48]
Notice how on both sides of the equation there is one coefficient (number being multiplied by x) and a constant (just a plain number). You want all constants to be on one side and all coefficients on the other. He’s how do to that:
2x+14=-21-5
I am choosing that all constants will be on the right side, so I will do the inverse operation of any constant on the left side to remove it. Here, a constant on the left side is 14. I will subtract 14 from both sides of the equation. Positive 14 minus 14 is zero, so it cancels out and removes it.
2x+14-14 = -21-5x
2x = -35-5x
See how the 14 is now gone? The equation looks much simpler now. Okay next, you can see that there is a coefficient on the “constant side” that I’ve chosen, so I am going to remove that. Negative 5 plus positive 5 equals zero. Do this on both sides of the equation.
2x+5x = -35-5x+5x
7x = -35
Now the equation is just two numbers. All that is left to do is divide by the last coefficient, 7, in this case.
7x/7 = -35/7
x = -5
8 0
1 year ago
Read 2 more answers
It costs $3.45 to buy 3 4lb of chopped walnuts. How much would it cost to purchase 7.5 lbs of walnuts? Explain or show your reas
Nuetrik [128]

<u><em>Answer:</em></u>

<u><em>8.05</em></u>

  1. <u><em>Step-by-step explanation:</em></u>
  2. <u><em>3.45 divide by 3 = 1.15</em></u>
  3. <u><em>1.15 times 7=8.05</em></u>
5 0
3 years ago
Which graph represents f(x)=6cos(4πx) ?
lesya692 [45]

Answer:

The graph representing f(x)=6cos(4πx) is shown in the attached file.

Step-by-step explanation:

The graph representing f(x)=6cos(4πx) is shown in the attached file.

6 0
3 years ago
I need help ASAP please with all of them
ratelena [41]

The third one I think I'm not sure

3 0
3 years ago
You earn $36 in 8 hours , how much would you earn in 17 hours . Explain
quester [9]
I hope this helps you

5 0
3 years ago
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