Answer:
x = 1
Step-by-step explanation:
Solve for x over the real numbers:
-1 + 2 + 1/x + 1/x = 3
-1 + 2 + 1/x + 1/x = 1 + 2/x:
1 + 2/x = 3
Bring 1 + 2/x together using the common denominator x:
(x + 2)/x = 3
Multiply both sides by x:
x + 2 = 3 x
Subtract 3 x + 2 from both sides:
-2 x = -2
Divide both sides by -2:
Answer: x = 1
Answer:
(2x • 5x) + (2x • -2)
Step-by-step explanation:
I think that's what you're looking for, you just distribute the 2x to both of the numbers in the parathesis
Answer:
b
Step-by-step explanation:
Answer:
None
Step-by-step explanation:
By using the equation a^2 +b^2=c^2 we can see if it will work.
Substitute a for 6 and b for 2 to get 6^2+2^2=40
when you 
you don't get 7 therefore you cant make any triangles
Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions
