Answer:
The answer is C
Step-by-step explanation:
I took the test
Let x be the smallest odd number.
x+(x+2)+(x+4)=147
3x+6=147
x=47
therefore the smallest odd no. is 47.
The length of a rectangle is 4 cm less than twice the width. express as an integer the maximum width of the rectangle when the perimeter is less than 78 cm.
Create an equation using the formula for area of a rectangle; area = width * length
(X + 2)(x + 3) = 600
Multiply the dimensions.
X^2 + 3x + 2x +6 = 600, or simplified x^2 +5x + 6 = 600.
Subtract 600 to get the following:
X^2 + 5x - 594 = 0
Factor by x:
(X - 22)(x + 27) = 0
Solve for x
X - 22 = 0
X = 22.
Use the POSITIVE VALUE of x as you can’t have a negative area for a room.
Then substitute 22 for x to get the dimensions
(22+ 2) or 24 for length and (22+3) or 25 for width.
