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bekas [8.4K]
3 years ago
11

I WILL GIVE RHE BRAINLIEST ANSWER

Mathematics
2 answers:
Rama09 [41]3 years ago
5 0

Answer:

Step-by-step explanation:

the triangles have the same shape and measures

devlian [24]3 years ago
3 0

Answer:

A, B

Step-by-step explanation:

Side lengths in cm:

Chloe: 30, 24, 18

Juan: 20, 16, 12

Look at the ratios of the corresponding side lengths:

30/20 = 3/2

24/16 = 3/2

18/12 = 3/2

Since all ratios are equal, by SSS Similarity, the triangles are similar.

Answer: A, B

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At the beginning of the week, Josh had 323232 computer games, 133\33, percent as many computer games as Peter had. By the end of
Ronch [10]

Answer:

Josh =24

Peter = 32

Step-by-step explanation:

Given

Beginning of Week

Josh = 32

Josh = 133\% * Peter

First, we calculate the amount Peter has at the beginning of the week

Josh = 133\% * Peter

Make Peter the subject

Peter = \frac{Josh}{133\%}

Peter = \frac{32}{133\%}

Peter = \frac{32}{1.33}

Peter = 24

When Josh gave out 25%.

The number (n) of computers is:

n = Josh * 25\%

n = 32 * 25\%

n = 8

This means that Josh gave out 8 computers.

So, the amount they both have is:

Josh =32 - 8

Josh =24

Peter = 24+8

Peter = 32

7 0
3 years ago
Suppose you deposit $2,000 in savings account that pays interest at an annual rate of 4%. If no money is added or withdrawn, det
GarryVolchara [31]
Using I = PRT

$2500 - $2000 = $2000 × 0.04 × t

$500 = 80t

t = $500 ÷ 80
t = 6.25 years

so the answer is 6
7 0
3 years ago
Suppose a simple random sample of size nequals64 is obtained from a population with mu equals 88 and sigma equals 8. ​(a) Descri
Ulleksa [173]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 88

\sigma_{\bar X}= 8

b) z=\frac{89.7-88}{\frac{8}{\sqrt{64}}}= 1.7

P(Z>1.7) = 1-P(Z

c) z =\frac{85.7-88}{\frac{8}{\sqrt{64}}}= -2.3

P(Z

d) z =\frac{87.35-88}{\frac{8}{\sqrt{64}}}= -0.65

z =\frac{90.5-88}{\frac{8}{\sqrt{64}}}= 2.5

P(-0.65

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 88, \sigma = 8

We select a sample size of n = 64

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sample mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 88

\sigma_{\bar X}= 8

Part b

We want this probability:

P(\bar X>89.7)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89.7 we got:

z=\frac{89.7-88}{\frac{8}{\sqrt{64}}}= 1.7

P(Z>1.7) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 85.7 we got:

z =\frac{85.7-88}{\frac{8}{\sqrt{64}}}= -2.3

P(Z

Part d

We want this probability:

P(87.35

We find the z scores:

z =\frac{87.35-88}{\frac{8}{\sqrt{64}}}= -0.65

z =\frac{90.5-88}{\frac{8}{\sqrt{64}}}= 2.5

P(-0.65

6 0
3 years ago
A box contains two defective Christmas tree lights that have been inadvertently mixed with eight nondefective lights. If the lig
REY [17]
Possibility 1: nondefective-defective-defective
possibility 2: defective-nondefective-defective

possibility 1: 8/10x 2/9 x 1/8 = 16/720=1/45
possibility 2: 2/10 x 8/9 x 1/8= 16/720=1/45

answer: 2/45
6 0
4 years ago
Is this correct? please help me if wrong
ser-zykov [4K]

Slope = rise/run = 3/16 miles per minute

Hope that  helps

6 0
4 years ago
Read 2 more answers
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