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mariarad [96]
3 years ago
15

Plz help me with Math!!

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

i dont know

Step-by-step explanation:

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Jane brought x shirts for $20 each and y skirts for $25 each she spent $210 in all. which equation represents this situation 2
miv72 [106K]

Answer:

Part A

20x + 25y = 210 --> D.

Part B

If jane purchased exactly 4 shirts she must have purchased Exactly ___ skirts. (round to the nearest tenth)

20*4 + 25y = 210 --> y = 5.2

is it possible for jane to purchase exactly 4 shirts? ____(yes or no)

no, because she can't buy 5.2 skirts.

5 0
3 years ago
Read 2 more answers
Which algebraic expression is a polynomial?
Degger [83]

Answer:

the last one is a polynomial

Step-by-step explanation:

8 0
2 years ago
Solve by elimination -2x+2y=6 and 4x×2y=-5
Valentin [98]

Answer:

x=-11/6, y=7/6. (-11/6, 7/6).

Step-by-step explanation:

-2x+2y=6

4x+2y=-5

-----------------

2(-2x+2y)=2(6)

4x+2y=-5

----------------------

-4x+4y=12

4x+2y=-5

----------------

6y=7

y=7/6

4x+2(7/6)=-5

4x+14/6=-5

4x=-5-14/6

4x=-30/6-14/6

4x=-44/6

x=(-44/6)/4

x=(-44/6)(1/4)

x=-44/24

simplify

x=-11/6

3 0
3 years ago
The sum of q and 5 whoever answers this please explain and answer
jok3333 [9.3K]

Answer:

It will be "q+5"

Step-by-step explanation:

When you add a number and a letter you just leave them like that. If you would to have a number multiplying a letter like "5q" and something else like "3q" when you add them together you will get "5q+3q=8q" In this case you can add them together because the number is multiplying the letter.

7 0
3 years ago
Find the roots of:
Elena-2011 [213]

\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

So the factorization is (x-1)² (2x-3)=0. So:

                     \bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2}  }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \  x^3-x^2-4=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

      |  1  -1  0  -4

  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

   | 6    7       9      2

<u>-2 |      -12    10     -2</u>

     6    -5     1       0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

         \bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}

                     \large\displaystyle\text{$\begin{gathered}\sf  \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}

6 0
2 years ago
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