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kirill [66]
2 years ago
13

You want to do a psychological experiment. On any given day, there is a 30% chance that your participant won’t show up. In addit

ion, there is a 10% chance that the stimulus presentation software won’t work. There is also a 5% chance that there is a problem with saving the data and a 2% chance that there are other problems like experimenter error. For the sake of simplicity, you can assume that all these events are independent. What is the probability that you will be able to do a successful experiment (be able to collect useful data) on any given day?
A. 0.59
B. 0.5
C. 0.49
D. 1
E. 0
Mathematics
1 answer:
Alisiya [41]2 years ago
6 0

Answer:

Option A

Step-by-step explanation:

Given that you want to do a psychological experiment. On any given day, there is a 30% chance that your participant won’t show up. In addition, there is a 10% chance that the stimulus presentation software won’t work. There is also a 5% chance that there is a problem with saving the data and a 2% chance that there are other problems like experimenter error.

Also given that each of the above four is independent.

Successful experiment can be done only if participant shows up (0.70), stimulus software works (0.90) , Saving the data (0.95) and no other problem (0.98)

Put to gether these independent events to use prob for all is product of probabilities

we have

the probability that you will be able to do a successful experiment (be able to collect useful data) on any given day

=0.7*0.9*0.95*0.98\\=0.58653

=0.59

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Answer:

<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>

Step-by-step explanation:

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  • Max has $5.50.
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From these statements, we can deduce algebraical expressions to solve the problem. Let's call q quarters, n nickels and d dimes.

q=n+8 (8 more quarters than nickels)

d=4n (he has four times as many dimes as he has nickels).

0.25q+0.05n+0.10d=5.50 (Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).

Let's replace the first two expressions into the third equation

0.25(n+8)+0.05n+0.10(4n)=5.50\\0.25n+2+0.05n+0.40n=5.50\\0.70n=5.50-2\\n=\frac{3.50}{0.70}\\ n=5

There are 5 nickels.

Now, we use this value to find the number of quarters

q=5+8=13

There are 13 quarters.

Also, d=4(5)=20

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Therefore, there are 13 quarters, 5 nickels and 20 dimes.

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