Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]
Answer:
-48
Step-by-step explanation:
Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,
- M(x,y) = 4x²y
- Mx(x,y) = 8xy
- L(x,y) = 10y²x
- Ly(x,y) = 20xy
- Mx - Ly = -12xy
Therefore, the line integral can be computed as follows

Using the linearity of the integral and Barrow's Theorem we have

As a result, the value of the double integral is -48-
Hello,
dom f={-2,-1,0,2}
Range={3,5,8}
Equation arrangement: 10 + [1/2]^4. 48
[1/2]^4 = 1/2 * 1/2 * 1/2 * 1/2 = 1/16
10 + [1/16] * 48
According to the law of BODMAS, we have to carry out multiplication operations before we carry out addition operations, therefore, we now have.
[1/16] * 48 = 3
Then, 10 +3 =13.
Thus, the final answer is 13.
29.5652% please give brainlest
The answer is 4. 2x plus 7 is equal to 15. First you subtract 7 from both sides then divide by 2 to get the answer 4. Hope this helps!