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3 years ago

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Val takes her four sons, Hal, Cal, Sal and Mal, to get their hair cut. It's crowded, so there's only time for two of them to get

a haircut. Val has to decide who goes first and who goes second. Below are her choices. Which ones are missing?

1 answer:

konstantin123 [22]3 years ago

6 0

first column... A) H then S

Second column... B) S then M

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

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Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

the lengths of the sides of BRAD are:

$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

$\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}$

Each side of KELY is twice the length of the corresponding side on BRAD. This makes the ratio of the sides 2:1 and the figures are similar.

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2 years ago

Read 2 more answers

I can go alone and fly and get 20% off

krek1111 [17]

The total cost to host the college is $341.1. The price of the student round trip fare is $304 and the taxi fare is going to cost you $12.6

5 0

3 years ago

Brainliest <br> Please do one of the above<br> (I would appreciate if you did more then one)

Temka [501]

Answer:

a) 52.5 ft. b)40.1ft c)12.5ft d) 72.6

Step-by-step explanation:

a) The height of the lighthouse is 84ft, and the angle of elevation is 58 degrees.

tan58=84/x

find x by dividing 84 by tan58, and you get 52.5ft.

b) do the same thing, except 131 is in the base of the right triangle shape. That being said, do tan17=x/131.

multiply 131 by tan17, and you get x=40.1 feet.

c) This question wants you to find the length of the slide, (basically the hypotenuse).

given the angle to be 46, do sin46=9/x

since sin is opp/hyp

9/sin46= 12.5ft

d) Find the angle of elevation by using inverse tan given the base to be 5, and the height to be 16ft.

tan^-1=(16/5)=theta

x=72.6 hope this helps!

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2 years ago

Read 2 more answers

What fracction is closets to -3/5, 2/5 0r 4/5

Andreas93 [3]

Answer:

2/5

Step-by-step explanation:

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3 years ago

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Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

DENIUS [597]

Answer:

The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.

The probability that a randomly chosen plate contains the sub-string HI is 0.002548 approximately.

Step-by-step explanation:

Consider the provided information.

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

Part (A)

Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.

Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.

The numbers of ways in which three letters followed by three digits can be chosen is: $26\times 26\times 26 \times 10 \times 10 \times10$

$26^3\times 10^3=17576000$

The numbers of ways in which two letters followed by four digits can be chosen is: $26\times 26\times 10 \times 10 \times 10 \times10$

$26^2\times 10^4=6760000$

Hence, the total number of ways are 17576000 + 6760000 = 24336000

Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.

Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are: $26^2=676$

The probability that a randomly chosen plate contains the number 2222 is:

$\frac{676}{24336000} \approx 0.000028$

Part (B)

The number of ways in which chosen plate contains the sub-string HI:

If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:

$26\times 1\times10^3+1\times 26\times10^3$

If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:

$1\times 10^4$

Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:

$1\times 10^4+26\times 1\times10^3+1\times 26\times10^3$

$62000$

From part (A) we know that the total number of ways to chose a number plate is 24336000.

The probability that a randomly chosen plate contains the sub-string HI is:

$\frac{62000}{24336000} \approx 0.002548$

7 0

3 years ago