Answer:
, cxzzzzznzlbzbkz jczczjczjvzvzv
Step-by-step explanation:
gxnzvzjvzvzbkzijzczvzvizjc
The dimension of the length and width of the rectangle with the given perimeter are 33ft and 16.5ft respectively.
<h3>What are the dimensions of the rectangle?</h3>
Perimeter of rectangle is expressed as;
P = 2( l + w )
Given that;
- Perimeter P = 99ft
- Let width w = x
- Length l = 2x
We substitute into the formular above.
P = 2( l + w )
99ft = 2( x + 2x )
99ft = 2x + 4x
99ft = 6x
x = 99ft/6
x = 16.5ft
Width = x = 16.5ft
Length = 2x = 2( 16.5ft ) = 33ft
Therefore, the dimension of the length and width of the rectangle with the given perimeter are 33ft and 16.5ft respectively.
Learn more about rectangles here: brainly.com/question/27612962
#SPJ1
Answer:
yards
Step-by-step explanation:
Answer:
Simplification
x(y+4)+3(2x+7y) = xy + 10x + 21y
= x(y + 10) + 21y
On evaluation when x=5 and y=6,
The expression is equal to 206
Step-by-step explanation:
Note that x and y are unknown variables.
On expansion,
x(y+4)+3(2x+7y)
= xXy + xX4 + 3X2x + 3X7y
= xy + 4x + 6x + 21y
= xy + 10x + 21y
On factorising,
xy + 10x + 21y = x(y + 10) + 21y
Evaluation when x=5 and y = 6
We substitute the given values of x and y into the simplified expression
xy + 10x + 21y
= 5X6 + 10X5 + 21X6
= 30 + 50 + 126
= 206
Therefore, on evaluation of the given expression, when x=5 and y=6, we get 206
Eight hundred and one point forty seven. Hope this helps!;)
