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kobusy [5.1K]
3 years ago
5

How do you do it? What do you take away and do after?

Mathematics
2 answers:
Nuetrik [128]3 years ago
5 0

hi sorry I can't help with that

babymother [125]3 years ago
4 0
The answer would be 7:46
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If anybody willing to help me with my geometry work that’s done by 6pm please contact me by my number 9014132287
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Do not listen to those bots
4 0
3 years ago
An EPA contractor needs to test the concentration of a substance in ten samples of the ground water. Seventy samples were
olga55 [171]

Answer:

Systematic sampling

Step-by-step explanation:

An EPA contractor needing to test the concentration of a substance in ten samples out seventy samples provided form a single source at regular time intervals.

For the contractor to effectively carry out the testing he has to employ a Non-probability system of sampling which is called Systematic sampling, because in systematic sampling we can assume the population size (x ) which in this case is 70 and the sample size( n ) to be 10

He will have to select ;  ( x / n )^th of the sampling frame for best results

7 0
3 years ago
What is the volume of the prism. 4.1 2.8 5.1
Fed [463]
So, when finding the volume, we would just add up every side, and from the question above, it look like that the numbers that we would be adding are the following above.

4.1+ 2.8+ 5.1=(11.2)

The volume would be 11.2
3 0
3 years ago
Read 2 more answers
Bethany sells roses and petunias. The expression 3r+2.5p3r+2.5p3, r, plus, 2, point, 5, p gives the cost (in dollars) of rrr ros
Lelechka [254]

Answer: The cost of 7 roses and 8 petunias is $41.

Step-by-step explanation:

Given, Bethany sells roses and petunias. The expression 3r+2.5p, gives the cost (in dollars) of r roses and p petunias.

Now  to find the cost of 7 roses and 8 petunias , put r= 7 and p= 8 in the above expression , we get

3(7)+2.5(8)=21+20\\\\=41

Hence, the cost of 7 roses and 8 petunias is $41.

5 0
3 years ago
Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

6 0
3 years ago
Read 2 more answers
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