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matrenka [14]
3 years ago
14

Write a multiplication equation using one whole number and one fraction that have a product of 18/8.

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0
18 * 1/8 because  you dont mutliply the denominator by a whole number, only the numerator.   

let me know if youre right
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It's exactly normal, because both populations are normally distributed.

Step-by-step explanation:

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Simplify 35.36 over 17
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it's

2.08

Step-by-step explanation:

<em><u>35.36 \div 17 = 2.08</u></em>

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Step-by-step explanation:

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Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
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Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

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Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
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