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2 years ago

Find the area of each composite figure. Round to the nearest TENTH if necessary.

Mathematics

1 answer:

bagirrra123 [75]2 years ago

4 0

Answer:

Step-by-step explanation:

split it in to two shape 3*7 and 6*2

7*3=21

6*2=12

21+12=33

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Is the relationship for Camille’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

Irina18 [472]

Answer:

It is a linear function, because the line has no curve, and the line is constant

Step-by-step explanation:

In a non linear function there would be a curve in the line, in this line there is no curve so therefore it is linear function.

4 0

2 years ago

Read 2 more answers

Write the vector v in the form aiplusbj, given its magnitude left norm Bold v right norm and the angle alpha it makes with the

photoshop1234 [79]

Answer:

$6\sqrt{3}i-6j$

Step-by-step explanation:

Given:

The magnitude, v=12

The angle $\alpha$ it makes with the positive x-axis = $150^0$

Now for a vector (x,y)

$\alpha =tan^{-1}(\frac{y}{x} )$ ; and

$v=\sqrt{x^2+y^2}$

Therefore:

$150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}$

$y=-\frac{x \sqrt{3}}{3}$

Similarly:

$v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2$

$144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}$

Recall that:

$y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3} \sqrt{3}}{3}=-6$

Therefore: $(x,y)=(6\sqrt{3}, -6)$

The vector in the form ai+bj is therefore:

$6\sqrt{3}i-6j$

6 0

3 years ago

how many servings are in a bag of trail mix that weighs 11 1/2 ounces and each serving of trail miix weighs 3/4 ounces

Mariulka [41]

let's firstly convert the mixed fraction to improper fraction, and then divide.

$\bf \stackrel{mixed}{11\frac{1}{2}}\implies \cfrac{11\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{23}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{23}{2}\div \cfrac{3}{4}\implies \cfrac{23}{2}\cdot \cfrac{4}{3}\implies \cfrac{23}{3}\cdot \cfrac{4}{2}\implies \cfrac{23}{3}\cdot 2\implies \cfrac{46}{3}\implies 15\frac{1}{3}$