Answer:
The smallest diameter of wrapper that will fit the candy bar is 6 cm
Step-by-step explanation:
The smallest diameter of the wrapper will have to be the length of the line AC.
We can observe that there are two similar triangles present in the shape there.
We have triangle ADE and triangle DCF
They are similar because their left side, base length, and right angle are equal.
We are given the length of the side AD for triangle ADE.
From the rules of similar triangles, we have that side DC will also equal 3 cm. because the two triangles are similar.
Hence AC will be 3cm + 3cm = 6 cm
The smallest diameter of wrapper that will fit the candy bar is 6 cm
B. because y is already solved
To the left is negaitive up is positive
so part 1 = D
part 2 = (-2,9) answer is C
Answer:
49.6
Step-by-step explanation:
A = πr2, (Pi r-squared)
A = (3.14)(8)2
A = (3.14) (64)
A = 198.4
but you need to take 1/4th of that since you are only looking at 1/4th of the circle so,
.25 x 198.4 = 49.6
