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s2008m [1.1K]
3 years ago
14

Isolate the x 3x+3y=-3

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

3x + 3y = -3    given

3x = -3y - 3   subtract 3y from both sides

x = -y -1        divide everything by 3

hope this helps <3

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4 0
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What is the solution to the inequality below?
madam [21]

Answer:

C. x < 25 and x ≥ 0

Step-by-step explanation:

Fastest and easiest way to do this is to graph the inequality and find out the lines.

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Find the complex zeros of <br><img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%7Bx%7D%5E%7B3%20%7D%20%20-%2013%20%7Bx%7D%5
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6 0
3 years ago
Use synthetic substitution to evaluate the polynomial P(x) = x^3-3x^2+4x-7 for x=3
Zina [86]

Answer:

\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}

Step-by-step explanation:

We are given polynomial as

P(x)=x^3-3x^2+4x-7

and it is divided by x=3 or x-3

we can use synthetic division

so, we got

Remainder =5

Quotient is

=x^2+0x+4

=x^2+4

we can write as

\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}


3 0
3 years ago
WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
4 0
3 years ago
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