Hello!
Let's find the area and see!
A = s^2
A = 3^2
A = 6 ft^2
Now, if you double 3, you get 6. 3 × 2 = 6 Find the area:
A = 6^6
A = 36 ft^2
ANSWER:
No, the area will not be doubled. The area was 9 ft^2 when the sides were 3 feet long. If you double 9, you get 18, since 9 × 2 = 18.
36 is not the double of 9, so no, the area is not double.
Considering the situation described, the classification of the runners is given as follows:
Dan - Ben - Alex - Curtis.
<h3>What is the classification of the runners?</h3>
The oldest came in second place. Ben is older than Alex, and Curtis is older than Dan, hence either Ben or Curtis finished second.
Alex ran the distance faster than Curtis, and Dan ran faster than Ben and Curtis, hence considering the above observation Ben finished second and the classification is:
Dan - Ben - Alex - Curtis.
A similar problem, in which a situation is interpreted, is given at brainly.com/question/5660603
#SPJ1
Answer:
5.5 ft
Step-by-step explanation:
therefore if you cut 11 in half you get 5.5
Do you have a typo? ; < this maybe
Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.
