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denis23 [38]
3 years ago
12

A plant is already 44 centimeterstall, and it will grow one centimeter every month. The plant's height, H (in centimeters), afte

r m months is given by the
following function
What is the plant's height after 23 months?
Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

67 centimetres

Step-by-step explanation:

44+23=67

44cm= already

1cm= every month

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M divided by 6 equals 21
Mice21 [21]

6x21=126   126/6=21

m= 126

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A business discovers a linear relationship between the number of shirts it can sell and the price per shirt. If the shirts cost
Setler [38]
It makes sense to let the # of shirts sold be the variable dependent upon the unit cost per shirt.

Notice that the # sold declines as the price increases.

Thus, the slope of this line will be -.
      
         8000 - 5000       3000 shirts
m = ------------------- = ----------------- = -200 shirts per dollar price increase 
             25 - 40                 -15
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How can this expression be written another way?
ale4655 [162]

Answer:

By the distributive property:

105 + 35m = 35(3 + m)

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1 year ago
What’s the converse of the Pythagorean theorem
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What is the Converse of the Pythagorean Theorem? The theorem states that if the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle
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4 years ago
Calculate all four second-order partial derivatives and confirm that the mixed partials are equal. f(x,y)= 2e^xy
nadya68 [22]
ANSWER TO QUESTION 1

The given function is

f(x,y)=2 {e}^{xy}

The partial derivative of f with respect to x means we are treating y as a constant. The first derivative is

f_{x} = 2y {e}^{xy}

and the second derivative with respect to x is,

f_{xx} = 2 {y}^{2} {e}^{xy}

ANSWER TO QUESTION 2

The given function is

f(x,y)=2 {e}^{xy}

The partial derivative of f with respect to y means we are treating x as a constant. The first derivative is

f_{y} = 2x{e}^{xy}

and the second derivative with respect to y is

f_{yy} = 2 {x}^{2} {e}^{xy}

ANSWER TO QUESTION 3

Our first mixed partial is

f_{xy}

We need to differentiate
f_{x} = 2y {e}^{xy}
again. But this time with respect to y.

Since this is a product of two functions of y, we apply the product rule of differentiation to obtain,

f_{xy} = 2y( {e}^{xy})' + ({e}^{xy})(2y)'

f_{xy} = 2xy {e}^{xy} + 2{e}^{xy}

ANSWER TO QUESTION 4

The second mixed partial is

f_{yx}

We need to differentiate
f_{y} = 2x{e}^{xy}

again. But this time with respect to x.

Since this is a product of two functions of x, we apply the product rule of differentiation to obtain,


f_{yx} = 2x({e}^{xy})' + ({e}^{xy})(2x)'

f_{yx} = 2xy {e}^{xy} + 2{e}^{xy}

Hence,

f_{xy} = 2xy {e}^{xy} + 2{e}^{xy} =f_{yx}
4 0
3 years ago
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