Answer:
Step-by-step explanation:
The given initial value problem is;
Let
Differentiating both sides of equation (1) with respect to 
, we obtain:
Differentiating both sides of equation (2) with respect to gives:
From equation (1),
Putting t=0 into equation (2) yields
Also putting t=0 into equation (3)
The system of first order equations is:
Answer:
63cm²
Step-by-step explanation:
Area of the shaded region = Area of the rectangle - Area of the two triangles
Area of the rectangle = 6(3+14)
Area of the rectangle = 6 * 17
Area of the rectangle = 102cm²
Area of the smaller triangle = 1/2 * 3 * 6
Area of the smaller triangle = 18/2 = 9cm²
Area of the larger triangle = 1/2 * 6 * (17-7)
Area of the larger triangle = 1/2 * 6 * 10
Area of the larger triangle = 60/2 = 30cm²
Area of the shaded part = 102 - (9+30)
Area of the shaded part = 102 - 39
Area of the shaded part = 63cm²
X^2+8x+x+8 simplifies to x^2+9x+8
Answer:
8x^{4}-2/3x^{2}-2/3x
Step-by-step explanation:
