A point in quadrant 4 could be (-4,-2)<span />
Find the velocity first, the "slope".
m=(y2-y1)/(x2-x1)
m=(95.5-53)/(4-2)
m=21.25 ? Your equations are wrong, I'll double check with another set of points...
m=(350.5-308)/(16-14)
m=21.25 LOL, yep none of your lines has the correct slope.
Anyway...
y=21.25x+b, using any point we can solve for the y-intercept, or "b", (2, 53)
53=21.25(2)+b
53=42.5+b
10.5=b so the distance to the lighthouse as a function of time is:
y=21.25x+10.5
So essentially, you should fire your teacher or burn that book you are using :)
1.4286 :D :D :D :D hope this helps
Answer:
Step-by-step explanation:
The volume of a cube is s*s*s or s^3 where s = the length of a side (2 in this case).
V = s^3
V = 2^3
V = 2*2*2
V = 8 cu in or 8 in^3
Answer:
Part A : y²(x + 2)(x + 4)
Part B: (x + 4) (x + 4)
Part C: (x + 4) (x - 4)
Step-by-step explanation:
Part A: Factor x²y²+ 6xy²+ 8y²
x²y²+ 6xy²+ 8y²
y² is very common across the quadratic equation , hence
= y² (x² + 6x + 8)
= (y²) (x² + 6x + 8)
= (y²) (x² + 2x +4x + 8)
= (y²) (x² + 2x)+(4x + 8)
= (y²) (x(x + 2)+ 4(x + 2))
= y²(x+2)(x+4)
Part B: Factor x² + 8x + 16
x² + 8x + 16
= x² + 4x + 4x + 16
= (x² + 4x) + (4x + 16)
= x( x + 4) + 4(x + 4)
= (x + 4) (x + 4)
Part C: Factor x² − 16
= x² − 16
= x² + 0x − 16
= x² + 4x - 4x - 16
= (x² + 4x) - (4x - 16)
= x (x + 4) - 4(x + 4)
= (x + 4) (x - 4)
