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erica [24]
3 years ago
7

Ada writes down at random a whole number larger than 1 and smaller than 11. Find the probability that it is....

Mathematics
2 answers:
Lisa [10]3 years ago
8 0
The answer is b hope it helpssssss
stiv31 [10]3 years ago
3 0
B even I hope it helpe
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Pollsters are concerned about declining levels of cooperation among persons contacted in surveys. A pollster contacts 78 people
UkoKoshka [18]

Answer:

Step-by-step explanation:

so i am confused what exactly do you want me to do?

3 0
4 years ago
A=444 b=213. 4÷a×b= can you help me plz
Lelechka [254]
First, let's input "a" and "b" into the equation:
(Don't forget to put brackets around the inputted numbers to show you are inputting "a" and "b")

<span>4 ÷ a × b = </span>4 ÷ (444) x (213)

Now we can solve!
 
               = 1.918
               = ~ 2

Hope this helps!
Feel free to message me if you have any questions :)
5 0
3 years ago
How are below 0, -10 and -20 related?<br> PLEASE HELP!!!!
Julli [10]

Answer:

It’s a way to show how things are related. It may be a mathematical pattern.

Step-by-step explanation:

7 0
3 years ago
(x^4)^2 perform the indicated operation
erica [24]

Answer:

x^8

Step-by-step explanation:

Since you are doing x^4 squared, you have to multiply the exponents.

4 * 2 = 8

x^8

8 0
4 years ago
Read 2 more answers
3. Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 blue balls. Find the probabili
choli [55]

Answer:

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

7C2 = 7! / 5!2! = 7*6 / 2 = 42 / 2 = 21

X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

8 0
3 years ago
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