Answer:
-89 +4i sqrt (3)
Step-by-step explanation:
sqrt(-48) - 89
sqrt(-1) sqrt(48) - 89
We know that sqrt(-1) = ±i
±i sqrt(48) - 89
±i sqrt(16)sqrt(3) - 89
±4i sqrt(3) - 89
Taking the principal square root
-89 +4i sqrt (3)
The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
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<span>The next number should be 4. If you look at every other number, even and odd alternate. 2 is even, 7 is odd, etc. Since 9 is odd, the next number should be even. To figure out what number specifically, you will want to break up the numbers into three columns. 2 3 __
7 12 17
8 9 10 From here, you can see that the pattern will be adding 1 for the top row, 5 for the middle row, and 1 for the bottom row. Since the unknown number is on the top right of the first row, you will add 1 to 3, and the answer is 4.</span>
