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4 years ago

Culinary Arts! Please help 3 questions is 15 points

Mathematics

1 answer:

Delvig [45]4 years ago

4 0

I think its

B: false
A: true
D: ensuring that smoke alarms are functional

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Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2, and the profit

Mademuasel [1]

Answer:

$y = -\frac{2}{3}x + 490$

gradient = = $-\frac{2}{3}$

y-intercept = $490$

Step-by-step explanation:

• The slope-intercept form of an equation takes the general form:

$\boxed{y = mx + c}$ ,

where:

m = slope,

c = y-intercept.

• We are given the equation:

$2x + 3y = 1470$

To change this into the slope-intercept form, we must make y the subject:

$3y = -2x + 1470$ [subtract $2x$ from both sides]

⇒ $y = -\frac{2}{3}x + \frac{1479}{3}$ [divide both sides by 3]

⇒ $y = -\frac{2}{3}x + 490$

• Comparing this equation with the general form equation, we see that:

m = $-\frac{2}{3}$

c = $490$ .

This means that the gradient is $\bf -\frac{2}{3}$ , and the y-intercept is $\bf 490$ .

6 0

2 years ago

Plzzzz help I know yall see it and there are some of yall who know this stuff so plzzzz help!!!!!! Pic down below!!

allochka39001 [22]

Ugggggggg idk soooooooo yeah

5 0

3 years ago

X -12 = 14 ---------------

balandron [24]

$x - 12 = 14 \\ x = 14 + 12 \\ x = 26$

it was help to you ❤︎❤︎❣︎❣︎★★★

4 0

3 years ago

Read 2 more answers

A student can do an average of 25 math problems an hour. If at a certain time of day, he has done 40 math problems, how many pro

yanalaym [24]

Answer:

Step-by-step explanation:

now: 40

after one hour: 40+25 = 65

after two hours: 65+25 = 90

7 0

3 years ago

Trigonometric question, 30 points, will give brainliest.

zheka24 [161]

hmmm first off let's convert the √3 +i to trigonometric form, and then use De Moivre's root theorem, bearing in mind that √3 and i or 1i are both positive, meaning we're on the I Quadrant.

$\bf (\stackrel{a}{\sqrt{3}}~,~\stackrel{b}{1i})\qquad \begin{cases} r=&\sqrt{(\sqrt{3})^2+1^2}\\ &\sqrt{3+1}\\ &2\\ \theta =&tan^{-1}\left( \frac{1}{\sqrt{3}}\right)\\\\ &tan^{-1}\left( \frac{\sqrt{3}}{3} \right)\\ &\frac{\pi }{6} \end{cases}~\hfill \implies ~\hfill 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right]$

$\bf ~\dotfill\\\\ \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] ~\dotfill$

$\bf \left[ 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right] \right]^3\implies 2^3\left[ cos\left( 3\cdot \frac{\pi }{6}\right) +i~sin\left( 3\cdot \frac{\pi }{6}\right) \right] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 8\left[cos\left( \frac{\pi }{2} \right) +i~sin\left( \frac{\pi }{2} \right) \right]~\hfill$

3 0

4 years ago