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n200080 [17]
3 years ago
13

1.

Mathematics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

Dice, Spinner

1, 1

1, 2

2, 1

2, 2

3, 1

3, 2

4, 1

4, 2

5, 1

5, 2

6, 1

6, 2

Step-by-step explanation:

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Which statement describes the graph of x = 4
Aleks04 [339]

Answer:

The graph of x=4 is a vertical line parallel to y-axis and having a x-intecept:(4,0) and having no y-intercept

Step-by-step explanation:

So I think that the answer would be this, which means answer 1!! Hope this helps

5 0
3 years ago
the perimeter of a triangle is 240 cm .the lengths of the sides are 3:4:5. calculate the legths of the longest and shortest side
Shkiper50 [21]

Shortest-60cm

Longest-100cm

8 0
3 years ago
A bus travels 90 km in 1.5 hours (with a constant speed). How far can it travel in 7.2 hours (with the same speed)?​
blondinia [14]

Answer:

distance=90km

time=1.5h

speed of the bus=distance /time

speed of the bus=90km/1.5h

speed of the bus=60km/h

therefore if 1.5h=60km/h

then 7.2h=(7.2x60)/1.5 =288km

5 0
2 years ago
Will mark branniest if gotten right
iris [78.8K]

Answer:

? = 30°

Step-by-step explanation:

All angles in a triangle add up to 180°

? + 130° + 20° = 180°

? = 180° - 130° - 20°

? = 30°

8 0
2 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
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