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MArishka [77]
2 years ago
9

RS=6y+2, ST=3y+7 and RT=54

Mathematics
1 answer:
Andru [333]2 years ago
5 0

Answer:

y = \frac{5}{3}

RS = 12

ST = 12

Step-by-step explanation:

hope it helps ☺️

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Please help me find the angle
34kurt

Answer:

79 degrees

Step-by-step explanation:

This is because <CBF is equivalent to <GFI

So, we know two angles in that triangle; 55 and 46.

By adding these together we get 101. In a triangle, the angles all add up to 180.

So we must subtract 101 from 180 and we will have that remaining angle.

3 0
3 years ago
Read 2 more answers
A company makes a cone-shaped container with a height of 15 in. The area of its base is about 78.8in.2 Approximately what is the
MakcuM [25]

Answer:

Approximately the volume of cone-shaped container is <u>393 in³</u>.

Step-by-step explanation:

Given:

A company makes a cone-shaped container with a height of 15 in.

The area of its base is about 78.8 in².

Now, to get the cone-shaped container volume.

So, we find the radius first by using formula:

Let the radius be r.

<u><em>(Using the value π = 3.14)</em></u>

A_{B}=78.8\ in^2.

A_{B}=\pi r^2

78.8=3.14\times r^2

<em>Dividing both sides by 3.14 we get:</em>

<em />25.09=r^2<em />

<em>Using square root on both sides we get:</em>

5.00=r

r=5\ in.

Thus, the radius (r) = 5 in.

<u>The height (</u>h<u>) = 15 in.</u>

Now, to get the volume of the cone-shaped container we put formula:

Volume=\pi r^2\frac{h}{3}

Volume=3.14\times 5^2\times \frac{15}{3} \\\\Volume=3.14\times 25\times 5\\\\Volume=392.50\ in^3.

Therefore, approximately the volume of the cone-shaped container is 393 in³.

7 0
3 years ago
What is x and y math help
Readme [11.4K]
<h3>Answer:</h3>
  • 20 cans of cola
  • 10 cans of root beer
<h3>Step-by-step explanation:</h3>

x and y are whatever you want them to be.

It can be convenient for solving a problem like this to use x and y to represent <em>what the problem is asking for</em>: the number of cans of cola and the number of cans of root beer. It is also convenient (less confusing) to use those variable names in the same order that the nouns of the problem are named:

... x = # of cans of cola

... y = # of cans of root beer

Then the problem statement tells you ...

... x + y = 30 . . . . . . . 30 cans total were bought

... x = 2y . . . . . . . . . . the number of cans of cola is twice the number of cans of root beer

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This set of equations is nicely solved by substitution: use the second equation to substitute for x in the first.

... (2y) +y = 30 . . . . . put 2y where x was

... 3y = 30 . . . . . . . . collect terms

... y = 10 . . . . . . . . . divide by 3

... 2y = x = 20

<em>You're not done yet. You need to answer the question the problem asks.</em>

Jared bought 20 cans of cola and 10 cans of root beer.

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<em>Comment on x and y</em>

You customarily see x and y as the variables of a problem. Personally, I like to use variables that remind me what they stand for. In this problem, I might use "c" for cans of cola and "r" for cans of root beer. Then when I've found the solution, I know exactly how it relates to what the question is asking.

Always start by writing down what the variables stand for (as we did here). Sometimes, this is called <em>writing a Let statement</em>: <u>Let</u> x = number of colas; <u>let</u> y = number of root beers.

<em>Comment on problems of this type</em>

When a proportional relationship is given between the items in a sum (2 cola cans for every root beer can), it is often convenient to work the problem in terms of groups of items. Here, a group of 3 items can consist of 2 cola cans and 1 root beer can. Then 30 items will be 10 groups, so 10 root beers and 20 colas. The problem is solved even before you can name the variables.

Even when the relationship isn't exactly proportional, you can add or subtract the extras and still work the problem this way. Had we said colas numbered 3 more than twice as many root beers, we could have our groups of 3 total 27 (30 less the 3 extra), giving 9 root beers and 21 colas (3 + 2·9).

8 0
3 years ago
The diameter of the base of the cone measures 8 units. The height measure 6 units. What is the volume of the cone?
ivolga24 [154]

Answer:

The  volume of the cone is  100.48 units³ approximately

Step-by-step explanation:

To find the volume of a cone with a diameter of 8 unit   and height of 6 units, we will follow the steps below;

first, write down the formula for calculating the volume of a cone

v= πr²\frac{h}{3}

where v is the volume of the cone

r is the radius    and h is the height of the cone

from the question given, diameter d = 8 units  but d=2r    which implies  r=d/2

r=8/2 = 4 units

Hence r= 4 units

height = 6 units

π is a constant and is ≈ 3.14

we can now proceed to insert the values into the formula

v= πr²\frac{h}{3}

v ≈ 3.14 × 4² × 6/3

v  ≈ 3.14 × 16 × 2

v ≈ 100 .48 units³

Therefore the  volume of the cone is  100 .48 units³ approximately

6 0
2 years ago
PLEASE HELP!!! Name the postulate or theorem that you can use to prove.....
bearhunter [10]

Answer:

HL theorem

Step-by-step explanation:

5 0
2 years ago
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