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3 years ago

How do you find the surface area and the volume to a composite figure?

Mathematics

1 answer:

Art [367]3 years ago

7 0

Answer:

वि स्कुल माध्यामिक विद्यालय निम्न माध्यामिक विद्यालय व्यवस्थापन समिति सम्पादन र प्रकाशनमा बुटवलबाट निस्कने एक्सरे साप्ताहिकमा एक पटक साप्ताहिकमा छापिएको थियो। प्रकाशित

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What percentage of 5/2 hours is 15 minutes?

elena-14-01-66 [18.8K]

Answer:

10 %

Step-by-step explanation:

15 mn = 1/4 h

We have :

$\frac{\frac{1}{4} }{\frac{5}{2} } =\frac{1}{4} \times \frac{2}{5} =\frac{2}{20} =\frac{1}{10}=0.1$

Then the percentage that 15 mn represents of 5/2 h is :

0.1 × 100 = 10 %

5 0

2 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

Two trains 500 miles apart accidentally are on the same track heading toward each other. The passenger train is traveling 80 mph

Natalka [10]

Answer:

2 miles

Step-by-step explanation:

Their combined speed (speed of closure) is 80 mph + 40 mph = 120 mph.

120 mi/h = 120 mi/(60 min) = 2 mi/min

The distance between the trains at the 1-minute mark is ...

(1 min) · (2 mi/min) = 2 mi

They were warned when two miles apart.

3 0

3 years ago

If anyone could help that would be great / right answer gets brainilest

Keith_Richards [23]

2.69 cm would be the answer

7 0

3 years ago

Read 2 more answers

PLS ANSWER ASAPThe function f(x) = 4x + 10 models the amount of money Francis makes

Andrei [34K]

Answer:

A 18

Step-by-step explanation:

f(x) = 4x + 10

f(2) = 4(2) + 10

f(2) = 8 + 10

f(2) = 18

6 0

3 years ago