If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Answer:
It's D.
Step-by-step explanation:
The graph of tan x passes through (0,0) whereas this graph passes through the point (pi/4 , 0) so it a horizontal translation to the right. We see that the period is 6 units along the x axis which is 6 * pi/4 = 3 pi/2.

A linear function has 1 as the highest power of the variable.
A. f(x) = 2 - 7x
here, the highest power of the variable x is 1.
Hence it is a LINEAR function.
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B. f(x) = 2 + x + x^2
here, the highest power of the variable x is 2.
Hence it is NOT a linear function.
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here, the highest power of the variable x is 1/2.
Hence it is NOT a linear function.
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Answer:
3n + 2.
Step-by-step explanation:
Just combine like terms.