Will give brainliest!!! 2.6(5.5p – 12.4) = 127.92 p=

Mathematics

1 answer:

Fiesta28 [93]3 years ago

4 0

Answer:

$p=11.2$

Step-by-step explanation:

Given $2.6(5.5p-12.4)=127.92$ , distribute to remove the parentheses:

$2.6\cdot 5.5p-2.6\cdot 12.4=127.92$

Simplify:

$14.3p-32.24=127.92$

Add 32.24 to both sides:

$14.3p=160.16$

Divide both sides by 14.3:

$p=\frac{160.16}{14.3}=\boxed{11.2}$

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I answered the rest of my questions but this one is confusing me

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Answer:

the answer is 36ft by 48ft

Step-by-step explanation:

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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.