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kirza4 [7]
3 years ago
5

Sophie drew a scale drawing of a house and its lot. The back patio is 3 centimeters wide in the drawing. The actual patio is 18

meters wide. What scale did Sophie use for the drawing?
Mathematics
1 answer:
wel3 years ago
4 0

Answer: 45?

Step-by-step explanation: Sorry If I'm wrong, I haven't learned this yet but I tried my best.

You might be interested in
What is 3/4÷1/2<br> Mathematics
Yuliya22 [10]

Answer:

1.5 or 3/2 or 1 1/2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
From exterior point L of circle O, tangent segments LP and LQ are drawn such that the measure of angle PLQ is 60 degrees. If a r
IrinaK [193]

Wow !  There's so much extra mush here that the likelihood of being
distracted and led astray is almost unavoidable.

The circle ' O '  is roughly 98.17% (π/3.2) useless to us.  The only reason
we need it at all is in order to recall that the tangent to a circle is
perpendicular to the radius drawn to the tangent point.  And now
we can discard Circle - ' O ' .
Just keep the point at its center, and call it point - O .

-- The segments LP, LQ, and LO, along with the radii OP and OQ, form
two right triangles, reposing romantically hypotenuse-to-hypotenuse. 
The length of segment LO ... their common hypotenuse ... is the answer
to the question.

-- Angle PLQ is 60 degrees.  The common hypotenuse is its bisector.
So the acute angle of each triangle at point ' L ' is 30 degrees, and the
acute angle of each triangle at point ' O ' is 60 degrees.

-- The leg of each triangle opposite the 30-degree angle is a radius
of the discarded circle, and measures 6 .

-- In every 30-60 right triangle, the length of the side opposite the hypotenuse
is  one-half the length of the hypotenuse.

-- So the length of the hypotenuse (segment LO) is  <em>12 </em>.


4 0
3 years ago
Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 mo
Katarina [22]

Given:

Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 monthly service fee. Paco is trying to keep his bill for the month below $30.

To Find:

The number of texts 't' Paco can send/receive in a month.

Answer:

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

Step-by-step explanation:

Paco wants to keep is monthly bill below $30.

We see that he has to pay a foxed monthly service fee of $15. This means he is only left with a limit of $30 - $15 = $15 for his monthly calls and texts.

That is, the amount he has to pay for texting and calling has to be less than $15.

For texts, the cell phone carrier charges $0.20 for sending/receiving texts.

For calls, he is charged $0.15 per minute.

Let the number of text messages Paco can send or receive in a month be denoted by 't'.

Let the number of minutes Paco can call in a month be denoted by 'c'.

Then, the total cost of text messages he can send or receive per month would be 0.20t and the total cost of the minutes he spends on calls would be 0.15c. Together, the sum of these has to be less than $15 if his monthly bill has to be kept less than $30 (accounting for the monthly service fee).

So,

0.20t+0.15c

The number of texts he can send will dpend on the number of minutes he spends on his calls. For Paco to spend maximum number of texts, he has to spend 0 minutes on calls.

So, putting c = 0, the aboce equation can be written as

0.20t+0

That is, Paco has to send and receive less than 75 texts.

So,

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

3 0
3 years ago
Read 2 more answers
Sides AB and DC of the rectangle are increased in length by 50% and sides AD and BC are decreased in length by 50%. What is the
emmainna [20.7K]

The percentage of change in the area of the rectangle is -25% ⇒ B

Step-by-step explanation:

The given is:

  • Sides AB and DC of the rectangle are increased in length by 50%
  • Sides AD and BC are decreased in length by 50%

We need to find the percentage change in the <em>AREA</em> of the rectangle

Assume that the length of AB ans DC is x units, and the length of AD and BC is y units

∵ The length of the sides AB and DC increased by 50%

∵ The length of AB and CD = x

- That means x will increase by 50% of x

∵ 50% of x = (50 ÷ 100) × x = 0.5 x

∴ The length is increased by 0.5 x

∴ The new length of AB and CD = x + 0.5 x = 1.5 x units

∵ The length of the sides BC and AD decreased by 50%

∵ The length of BC and AD = y

- That means y will decrease by 50% of y

∵ 50% of y = (50 ÷ 100) × y = 0.5 y

∴ The length is decreased by 0.5 y

∴ The new length of BC and AD = y - 0.5 y = 0.5 y units

∵ The area before the change = x × y = xy units²

∵ The area after the change = 1.5 x × 0.5 y = 0.75 xy units²

∵ The new area is less than the old area

∴ The area is decreased

- To find the the percentage of change in the area subtract the

   new area from the old area and divide the difference by the

    old area and then multiply the quotient by 100%

∴ The percentage of the change = \frac{xy-0.75xy}{xy} × 100%

∴ The percentage of the change = \frac{0.25xy}{xy} × 100%

∴ The percentage of the change = 0.25 × 100%

∴ The percentage of the change = 25%

∴ The area of the rectangle is decreased by 25% ⇒ (-25%)

The percentage of change in the area of the rectangle is -25%

Learn more:

You can learn more about the percentage in brainly.com/question/12960754

#LearnwithBrainly

7 0
4 years ago
Consider the extremely large integers $$x = 2\cdot 3\cdot 5\cdot 7\cdot 11\cdot 13\cdot 17\cdot 19\cdot 23\cdot 29$$ and $$y = 2
-BARSIC- [3]

Answer:

Hence, greatest common divisor of x and y is : 29.

Step-by-step explanation:

We are given:

We are given the large integers 'x' and 'y' as:

x=2×3×5×7×11×13×17×19×23×29

We could clearly see that x is the multiplication of all the prime numbers starting from 2 and ending at 29.

we are given y as:

y=29×31×37×41×43×47×53×59×61×67

Clearly we could see that y is also a multiplication of all the prime numbers starting from 29 and ending at 67.

<em>" In mathematics, the greatest common divisor (gcd) of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers "</em>

Hence from the expression of x and y we could clearly see that the only common divisor that divides both x and y is 29.

Hence, greatest common divisor of x and y is 29.

8 0
4 years ago
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