Step-by-step explanation:
Remember when expanding radicals,
When expanding radicals into two radicals, we don't let our radicand have two negative answers.
We don't do this
Answer:
what do you mean?
Step-by-step explanation:
Answer:
a.) dx3x² + 2
Use the properties of integrals
That's
integral 3x² + integral 2
= 3x^2+1/3 + 2x + c
= 3x³/3 + 2x + c
= x³ + 2x + C
where C is the constant of integration
b.) x³ + 2x
Use the properties of integrals
That's
integral x³ + integral 2x
= x^3+1/4 + 2x^1+1/2
= x⁴/4 + 2x²/2 + c
= x⁴/4 + x² + C
c.) dx6x 5 + 5
Use the properties of integrals
That's
integral 6x^5 + integral 5
= 6x^5+1/6 + 5x
= 6x^6/6 + 5x
= x^6 + 5x + C
d.) x^6 + 5x
integral x^6 + integral 5x
= x^6+1/7 + 5x^1+1/2
= x^7/7 + 5/2x² + C
Hope this helps
Answer:
The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third
Step-by-step explanation:
The student was wrong in his evaluation because the correct result should be 1 1/3 (one and one-third) and not 16 and one-third
The expression '1/3 more than the product of four and a number' means
(4g + 1/3)
Evaluating the expression when g = 1/4
You will have
4×1/4 + 1/3
= 1/1 + 1/3
Find the LCM of 1 and 3 and add
= (3+1)/3
=4/3
= 1 1/3
The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third
Answer:
5r+12
Step-by-step explanation:
