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liraira [26]
3 years ago
13

Use number line f to answer the questions.

Mathematics
2 answers:
Andre45 [30]3 years ago
6 0

Answer:

r u in school

Step-by-step explanation:

snow_lady [41]3 years ago
3 0
Answer :
67 is answer.
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Suppose that 37% of college students own cats. If you were to ask random college students if they own a cat what would the proba
Likurg_2 [28]

Using the binomial distribution, the probabilities are given as follows:

a) 0.37 = 37%.

b) 0.5065 = 50.65%.

c) 0.3260 = 32.60%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the fixed parameter is:

p = 0.37.

Item a:

The probability is P(X = 1) when n = 1, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{1,1}.(0.37)^{1}.(0.63)^{0} = 0.37

Item b:

The probability is P(X = 3) when n = 3, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.37)^{3}.(0.63)^{0} = 0.5065

Item c:

The probability is P(X = 2) when n = 4, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.37)^{2}.(0.63)^{2} = 0.3260

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
Evaluate c/2 - 3 + 6/d when c=14 and d=13???
Kazeer [188]

c/2-3+6/d

substitute c=14 and d=13:

14/2-3+6/13

simplify:

7-3+6/13

4+6/13

multiply 4 by 13/13 to group like terms (for a fraction):

52/13+6/13

combine:

58/13

Therefore, the answer is 58/13 or around 4.462

5 0
3 years ago
What is the ratio representation of the leg rule for this triangle
ValentinkaMS [17]

Answer:

Where's the triangle? Do you have an image?

6 0
2 years ago
What day is today What day is today plus tommorow
Ludmilka [50]

Answer:

today is friday and tomorrow is saturday

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
24 POINTS!!!! help please. No work needed....
Mrrafil [7]
I’m more than happy to help you
8 0
3 years ago
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