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pogonyaev
3 years ago
12

Help pls and explain !!

Mathematics
2 answers:
Alborosie3 years ago
8 0
Help pls and explain !!

if c/d - a/b =x, a =2c, and b=5d, what is the value of c/d in terms of x?

D) 5/3 X
Aneli [31]3 years ago
6 0

Answer:

d) 5/3 x

Step-by-step explanation:

You substitute a for 2c and b for 5d, so your equation will look like this:

c/d - 2c/5d = x

Then you just simplify into x by making c/d into 5c/5d so you have a common denominator.

5c/5d - 2c/5d = x

3c/5d = x

5/3 is your answer

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Simplify . 4y4 4y8 8y4 8y8
Tanya [424]

Answer:

B

Step-by-step explanation:

Just did it.

4 0
3 years ago
Find the least number which when divisible by 20, 24, 32 and 38 leaves a remainder 5 in cach case
Olegator [25]

Answer:

18245

Step-by-step explanation:

We have to use L.C.M,

L.C.M(20,24,32,38)

2|20,24,32,38

2| 10 ,12 ,16 ,19

2| 5 , 6 , 8 , 19

2| 5 , 3 , 4 , 19

2| 5 , 3 , 2 , 19

L.C.M = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 3 x 19

          = 18240

Now for each case remainder is 5,

So the number is 18240+5

=> 18245

7 0
2 years ago
The area of a rectangular barnyard is given by the trinomial 6x2 + 7x – 20. What are the possible dimensions of the barnyard? Us
sertanlavr [38]
Area of a rectangular barnyard: A=6x^2+7x-20
A=6(6x^2+7x-20)/6
A=[(6^2)(x^2)+7(6x)-120]/6
A=[(6x)^2+7(6x)-120]/6
A=(6x+15)(6x-8)/6
A=(6x+15)(6x-8)/[(3)(2)]
A=(6x/3+15/3)(6x/2-8/2)
A=(2x+5)(3x-4)
A=bh
b=2x+5; h=3x-4
Answer: The possible dimensions of the barnyard are 2x+5 and 3x-4
8 0
2 years ago
Can someone please help me
Daniel [21]

Answer:

(-7.5, 3.5)

Step-by-step explanation:

midpoint \:  = ( \frac{x1 + x2}{2} \:  , \:  \frac{y1 + y2}{2} )

= ( \frac{ ( - 5) + ( - 10)}{2} , \frac{(5) + (2)}{2} )

= ( \frac{ - 15}{2} , \frac{7}{2} )

= ( - 7.5,3.5)

8 0
2 years ago
PLEASE HELP I WILL MARK BRAINLIEST!<br> Question is in the image.
deff fn [24]

Answer:

8

Step-by-step explanation:

The interquartile range of a data set is the difference between the upper and lower quartiles.

First, put the values in order from least to greatest:

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

To find the upper quartile, we need to first find the median.

The median of this data set is 11, because it is in the middle of the values.

The upper quartile is the median of all the numbers to the left of 11.

The median of 8, 9, 9, 9, and 10 is 9, because it's in the middle.

So the upper quartile is 9.

The lower quartile is the same, but to the right of 11. The median of 13, 15, 17, 18, and 22 is 17 because it's in the middle.

Now, to find the interquartile range, find the difference between 18 and 9.

17 - 9 = 8

5 0
2 years ago
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