F(x) = -x² + 4
g(x) = 6x
(g - f)(3) = 6(3) - (-(3)² + 4)
(g - f)(3) = 18 - (-9 + 4)
(g - f)(3) = 18 - (-5)
(g - f)(3) = 18 + 5
(g - f)(3) = 23
<span>
</span>
Work done on cart
:
W
=
6000
J
Kinetic energy of cart
:
E
K
=
6000
J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300
N
⋅
20
m
⇒
W
=
300
kg
⋅
m s
−
2
⋅
20
m
⇒
W
=
300
⋅
20
kg
⋅
m
2
s
−
2
⇒
W
=
6000
kg
⋅
m
2
s
−
2
∴
W
=
6000
J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000
The solution would
be like this for this specific problem:
(cos^2x-1)/cosx+1
cos^2x-1= (cosx+1)(cosx-1)
cosx-1
<span>I am hoping that
this answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.</span>
Let x be the cost of dryer, y be the cost of washer
x + y =821
x-79 = y
combine 2 equation
we got
x + (x-79) = 821
2x + 79 = 821
2x = 742
x=471
The cost of dryer is $471
Answer:
3(n+4)
Step-by-step explanation:
you will take common
3(n+4)
