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svetoff [14.1K]
4 years ago
11

Molecule- Mass Conversions 1. How many molecules are there in 23.4 grams of magnesium?

Chemistry
1 answer:
Vilka [71]4 years ago
6 0

Answer:

5.78\times 10^{23} molecules

Explanation:

m = Mass of Magnesium = 23.4 g

M = Molar mass of Magnesium = 24.305 g/mol

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

Number of moles is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{23.4}{24.305}\ \text{mol}

Number of molecules is given by

nN_A=\dfrac{23.4}{24.305}\times 6.022\times 10^{23}=5.78\times 10^{23}

The sample has 5.78\times 10^{23} number of molecules.

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If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3
ss7ja [257]

Answer:- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

= 39.0gPbI_2

18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2, so the answer is, 27.7 g of PbI_2 are produced.

8 0
3 years ago
Balance the following equation and answer the question. ___CuCl + ___ H2S ------ ___ Cu2S + ___ HCl If 1.2 moles of CuCl is mixe
brilliants [131]

Answer:

A. 2CuCl + H2S —> Cu2S + 2HCl

B. 0.6 mole of Cu2S

Explanation:

A. The balancing equation.

The equation can be balance as follow:

CuCl + H2S —> Cu2S + HCl

There are 2 atoms of Cu on the right side and 1 atom on the left. It can be balance by putting 2 in front of CuCl as shown below:

2CuCl + H2S —> Cu2S + HCl

There are 2 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 2 in front of HCl as shown below:

2CuCl + H2S —> Cu2S + 2HCl

Now we can see that the equation is balanced.

B. Determination of the number of mole of Cu2S produced by the reaction 1.2 mole of CuCl.

This is illustrated below:

2CuCl + H2S —> Cu2S + 2HCl

From the balanced equation above, 2 moles of CuCl reacted to produce 1 mole of Cu2S.

Therefore, 1.2 mole of CuCl will react to produce = 1.2/2 = 0.6 mole of Cu2S.

Therefore, 0.6 mole of Cu2S is produced from the reaction of 1.2 mole of CuCl.

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4 years ago
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Two very big differences between Kelvin and Celsius: 1. Kelvin has no negative numbers, 2. All Celsius amounts are 273 degrees less than it’s equal kelvin amount
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