Answer:
C6 H12 O6 + 6 O2 → 6 C O2 + 6 H2 O + energy
Explanation:
Answer:
54.5%
Explanation:
The percentage composition of oxygen in C₆H₈O₆ can be obtained as follow:
Molar mass of C₆H₈O₆ = (12×6) + (8×1) + (16×6)
= 72 + 8 + 96
= 176 g/mol
Next, there are 6 oxygen atoms in C₆H₈O₆. Therefore the mass of oxygen in C₆H₈O₆ is:
Mass of Oxygen = 16 × 6 = 96 g
Finally, we shall determine the percentage composition of oxygen in C₆H₈O₆ as follow:
Percentage of oxygen =
Mass of Oxygen/mass of C₆H₈O₆ × 100
Percentage of oxygen = 96 / 176 × 100
Percentage of oxygen = 54.5%
Thus, the percentage composition of oxygen in C₆H₈O₆ is 54.5%.
Answer:
0.025 g C6H12O6
Explanation:
ppm = (g solute/ g solution)* 10^6
g solute= (ppm * g solution)/ 10^6
g solute = (250 ppm * 100 g)/10^6
g solute=0.025 g C6H12O6
Answer:
15 grams of water will absorb 2,500 Joules in going from 20.0 to 60.0 C.
Explanation:
The heat involved in raising a mass (m) of a substance with a specific heat (c) from one temperature to another (Delta T) is given by:
Heat = mc(Delta T)
2,500 Joules = m*(4.186J/gC)*(60C-20C)
2,500 Joules = m*(4.186J/gC)*(40C)
2,500 Joules = m*(4.186J/gC)*(40C)
m = (2,500J)/(4.186*40J/g)
m = 14.93 grams
Answer: 23.53g
Explanation:
5.2/(2x16) = 0.1625 mol
0.1625 x 2 = 0.325 mol
0.325 x (23 x 2 + 16 x 2) = 78 x 0.325 = 23.53g