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grandymaker [24]
3 years ago
12

CAN SOMEONE HELP ME ASAP

Mathematics
2 answers:
melomori [17]3 years ago
8 0

Answer:

3 minutes

Step-by-step explanation:

Apricot prints 8 pages per minute, the Sure-fire prints 12.

That means Wafa's brother's printer is 1.5 times faster than Wafa's own.

That means his printer can print the document in 4.5min / 1.5 = 3min

BARSIC [14]3 years ago
5 0

Answer:

3 minutes

Step-by-step explanation:

To calculate this, you have to multiply 4.5 minutes by 8. This will give you the amount of pages that Wafa will print.

4.5 x 8 = 36 pages

Now that you have the amount of pages, you should divide it by the speed of the Sure-Fire printer. 12 ppm means that 12 pages can be printed in 1 minute.

36/12 = 3

Therefore, it would take 3 minutes if Wafa were to use her brother's Sure-Fire printer.

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777dan777 [17]

Answer:

Solve it yourself

Step-by-step explanation:

4 0
3 years ago
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
2 years ago
The angle looking up at the sun is 70°. A flagpole casts a shadow of 15 ft. Draw a diagram and find the height of the flagpole
deff fn [24]

Answer:

The length of the flagpole be 41.2 ft .

Option (A) is correct .

Step-by-step explanation:

As given

The angle looking up at the sun is 70°.

A flagpole casts a shadow of 15 ft .

Now by using the trignometric identity .

tan \theta = \frac{Perpendicular}{Base}

\ theta = 70^{\circ}

tan\ 70^{\circ} = \frac{AB}{BC}

BC = 15 ft

tan 70° = 2.75 (Approx)

2.75 = \frac{AB}{15}

AB = 2.75 × 15

     = 41.2 ft

Therefore the length of the flagpole be 41.2 ft .

Option (A) is correct .

4 0
3 years ago
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Sav [38]

Answer:

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Step-by-step explanation:

OMP. = $56

D. = 25%

0.25 * $56 = $14

SP. = $56-$14=$42

CD. = 20% of Selling price

= 0.20 * $42 = $8.40

FSP. = $42-$8.40      = $33.60

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3 years ago
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Dmitriy789 [7]

Answer:

Bruv, this is an English server.

Step-by-step explanation:

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2 years ago
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