Factor 42x+28y using the GCF

The theoretical probability of an event occurring is 2/5. Which best describes the experiment probability associated with this e

pogonyaev

The answer is out of every 5, the desired out come will be approximately 2 times.

5 0

3 years ago

Read 2 more answers

1 Point

Ivahew [28]

Answer:

The answer is D

Step-by-step explanation:

You can find it by expanding the equation in the form of y = mx + b :

y - 4 = 3(x + 1)

y - 4 = 3x + 3

y = 3x + 3 + 4

y = 3x + 7

Then, looking at the equation "b" is a y-intercept. The line that touch/passes through y-axis is called y-intercept. From the equation, we know that 7 is the y-intercept.

By looking at the diagram, only Graph D is suitable for this equation because the line has touches 7 at y-axis.

5 0

2 years ago

You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre

ra1l [238]

Answer:

1) Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

$\bar X=640$ represent the sample mean

$\sigma=150$ represent the population standard deviation

$n=40$ sample size

$\mu_o =500$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Step1:State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:

Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

Step 2: Calculate the statistic

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

We can replace in formula (1) the info given like this:

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value

Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

7 0

2 years ago

You earn $8 per hour for babysitting plus $0.75 per mile that she has to drive . Write an equation to represent this situation a

Hoochie [10]

Answer:

8x+$0.75x.

Step-by-step explanation:

8x is the hours you babysit and $0.75x the miles you drive.

3 0

2 years ago

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What is 15267 times 16459 then divide by 7?

lesya [120]

Answer:

33297327

Step-by-step explanation:

(15267 * 15267) ÷ 7

= 15267 * 15267

= 233081289 ÷ 7

= 33297327

Hope this helps! :)

7 0

2 years ago