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3 years ago

14

Identify the correct equation that matches the graph.

2 answers:

dezoksy [38]3 years ago

8 0

Answer:

A, y=1/4x+2

Step-by-step explanation:

All of the equations are the same except forthe slope. Look at the points where the line crosses the points, I chose (0,2) and (4,3). The line goes up one and over four from the first point to the second point. Since it’s rise over run, up and over, it’s 1/4x

kobusy [5.1K]3 years ago

4 0

Answer:

I don't know either B or D ........

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17) Find the surface area of the right triangular prism shown below:<br> 5<br> 2<br> 5/2<br> 3/2

harkovskaia [24]

Answer:

D

Step-by-step explanation:

They didn't provide the number for one of the faces btw..

7 0

2 years ago

What is the answer to this i need help please

Contact [7]

Answer:

-(√2) + √3

Step-by-step explanation:

2√3 - (√2 + √3)

2√3 - √2 - √3

2-1√3 - √2

√3 - (√2)

or.

-(√2) + √3

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3 years ago

A software company sells an education version (e) and a commercial version (c) of its popular image editing software. During the

geniusboy [140]

Make 2 equations let x=150 y=600/180000 than plug and chug

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3 years ago

Read 2 more answers

Help me with this please

Pavel [41]

bro

Step-by-step explanation:

5 0

2 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

3 years ago