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Nana76 [90]
3 years ago
14

Identify the correct equation that matches the graph.

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0

Answer:

A, y=1/4x+2

Step-by-step explanation:

All of the equations are the same except forthe slope. Look at the points where the line crosses the points, I chose (0,2) and (4,3). The line goes up one and over four from the first point to the second point. Since it’s rise over run, up and over, it’s 1/4x

kobusy [5.1K]3 years ago
4 0

Answer:

I don't know either B or D ........

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We have been given graph of a downward opening parabola with vertex at point (6.5,42.25). We are asked to write equation of the parabola in standard form.

We know that equation of parabola in standard form is f(x)=ax^2+bx+c.

We will write our equation in vertex form and then convert it into standard form.

Vertex for of parabola is y=a(x-h)^2+k, where point (h,k) represents vertex of parabola and a represents leading coefficient.

Since our parabola is downward opening so leading coefficient will be negative.

Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:

0=-a(0-6.5)^2+42.25

0=-a(42.25)+42.25

-42.25=-a(42.25)+42.25-42.25

-42.25=-42.25a

a=1 Divide both sides by -42.25

So our equation in vertex form would be f(x)=-(x-6.5)^2+42.25.

Let us convert it in standard from.

f(x)=-(x^2-13x+42.25)+42.25

f(x)=-x^2+13x-42.25+42.25

f(x)=-x^2+13x

Therefore, the equation of function is standard form would be f(x)=-x^2+13x.

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