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Archy [21]
3 years ago
6

YO help a girl out

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

6m-mn, or 5m-n.

7y+42+5y+30, or 12y+72.

Not sure exactly what you're asking for the third and fourth, but these are the first two simplified.

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If rs =3x + 1, st = 2x- 2 ,and rt = 64,find the value of x
stealth61 [152]
             rs + st = rt     Plug in the values
3x + 1 + 2x - 2 = 64   Combine like terms (1 and -2)
       3x -1 + 2x = 64   Combine like terms (3x and 2x)
            -1 + 5x = 64   Add 1 to both sides
                  5x = 65   Divide both sides by 5
                    x = 13
3 0
3 years ago
Please help me with this question
wel
If I could get more context then that would help. Because an exponent being an odd number doesn’t do anything, so it could be either a negative or a positive
4 0
3 years ago
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Shalnov [3]

Answer:

D. 150 metres

Step-by-step explanation:

speed = (60) times 5/18 = 50/3

lenght of the train = (speed x time)

lenght = 50/3 times (9)

   = 150 m.

8 0
3 years ago
What is 0.35 as a simplified fraction and why??
avanturin [10]

Answer:

7/20

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Derive the equation of the parabola with the focus <br> is (-7,5) and the directrix of y=-11
Volgvan
So, notice, the focus point is at -7, 5, and the directrix is at y = -11.

keep in mind that the vertex is half-way between those two fellows, and the distance from the vertex to either one of them is "p" units, check the picture below.

with that focus point and that directrix, the half-way over the axis of symmetry will be -7, -3, that's where the vertex is at, and notice the distance "p", is 8 units.

since the parabola is opening upwards, "p" is positive 8.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;4p(x- h)=(y- k)^2&#10;\\\\&#10;\boxed{4p(y- k)=(x- h)^2}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ( h, k)\\\\&#10; p=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;h=-7\\&#10;k=-3\\&#10;p=8&#10;\end{cases}\implies 4(8)[y-(-3)]=[x-(-7)]^2&#10;\\\\\\&#10;32(y+3)=(x+7)^2\implies y+3=\cfrac{1}{32}(x+7)^2&#10;\\\\\\&#10;y=\cfrac{1}{32}(x+7)^2-3

8 0
3 years ago
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