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2 years ago

Help me out thank youuuu sooo much !!!

Mathematics

1 answer:

lozanna [386]2 years ago

8 0

Answer/Step-by-step explanation:

There are actually two methods that can be used to calculate AC (x):

1. Using Pythagorean Theorem

2. Using Trigonometric Function

1. Using Pythagorean Theorem, we have:

x = √(15² + 20²)

x = √625

x = 25 units

2. Using Trigonometric Function:

Reference angle = 37°

Adjacent = 20

Opposite = 15

Hypotenuse = x

Apply SOH:

Sin 37 = Opp/Hyp

Sin 37 = 15/x

x × Sin 37 = 15

x = 15/sin 37

x = 24.9246021 ≈ 25 units (nearest whole number)

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Help! I don't understand this.

OleMash [197]

Answer:

x > 9.

Step-by-step explanation:

Here it is just simplifying the inequality.

6 - 2/3x < x - 9

Add 2/3x to both sides.

6 < 5/3x - 9

Add 9 to both sides.

15 < 5/3x

Multiply by 3/5.

9 < x

Flip it.

x > 9.

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2 years ago

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My I pless have a little help play just with one little thing (3^2 * 3^3)2

Ymorist [56]

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2 years ago

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The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the

umka21 [38]

This is probably way overcomplicated but i cant remember how to do it
w = n
l = 2n+1
w*l = 66
n(2n+1) = 66
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3 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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3 years ago

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Goshia [24]

Answer:

8.25 is the answer.

Step-by-step explanation:

Hope this helps!

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2 years ago

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