All categories

3 years ago

Zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics

1 answer:

Kisachek [45]3 years ago

3 0

Mmmmmmmmmmmmmmmmkkkkkkkkkkkkkkk

You might be interested in

I need help answering the question

Troyanec [42]

x = 15 + 4y that is what I got out of it

3 0

3 years ago

3. What are the roots of the polynomial y = x³ - 8?

zzz [600]

Step-by-step explanation:

x^3 is a perfect cube, 8 is a perfect cube, so we use difference of cubes.

${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )$

Cube root of x^3 is x.

Cube root of 8 is 2

a=x

b= 2.

$(x - 2)( {x}^{2} - 2x + 4)$

Set these equations equal to zero

$x - 2 = 0$

$x = 2$

${x}^{2} - 2x + 4 = 0$

If we do the discriminant, we get a negative answer so we would have two imaginary solutions,

Thus the only real root is 2.

If you want imaginary solutions, apply the quadratic formula.

$1 + i \sqrt{ 3 }$

and

$1 - i \sqrt{3}$

4 0

1 year ago

Distributive property -2(X-3)=5(2X+3) A) 1 B) 6 C) -3/4

iragen [17]

It's C) -3/4

If you need the steps let me know. (:

8 0

3 years ago

Read 2 more answers

Pls help I’ll give the big brain award or whatever

andre [41]

Answer:

-0

-1

-2

Step-by-step explanation:

300x80=24,000

7 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

Conclusion:-

The area of the region between the graph of the given function and the x-axis = 25,351 units²

6 0

3 years ago