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xz_007 [3.2K]
3 years ago
9

13. Give an example of a linear equation that is parallel to the y-axis.

Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

x=1

Step-by-step explanation:

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Please help
aalyn [17]

Step-by-step explanation:

4(2a + 5) that's the answer

3 0
3 years ago
Read 2 more answers
4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

4 0
3 years ago
B) 75: 125 help me solve it
mash [69]

75:125

divide both sides by 25

75/25= 3

125/25= 5

Answer: 3:5

4 0
4 years ago
Can Someone Help REAL QUICK Me. ? Please
bagirrra123 [75]

Answer: Option 3

Step-by-step explanation:

You can make equivalent fractions by multiplying or dividing both top and bottom by the same amount. You only multiply or divide, never add or subtract, to get an equivalent fraction.

I hope this helps.

5 0
3 years ago
BESTIES HELP PLEASE!!?!?!?!?&$
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Answer:

Yes no yes yes

Step-by-step explanation:

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