Set up the equation by writing the number of students in the ratio as a fraction:
3/4= (245-x)/x Cross multiply:
3x= 4(245-x) Multiply on right:
3x= 980-4x Add 4x on both sides:
7x= 980 Divide both sides by 7:
x= 140 this is how many girls there are. And:
245-140= 105= boys
Answer:
QR = 65.4 m
Step-by-step explanation:
a. Apply Law of Cosines to find QR:
p² = q² + r² - 2qr × Cos P
p = QR = ?
q = PR = 150 m
r = PQ = 120 m
P = 25°
Plug in the values
p² = 150² + 120² - (2)(150)(120) × Cos(25°)
p² = 22,500 + 14,400 - 36,000 × 0.9063
p² = 36,900 - 32,626.8
p² = 4,273.2
p = √4,273.2
p ≈ 65.4 m (nearest tenth)
QR = 65.4 m
Thank you thank you very much
Answer:
Step-by-step explanation:
Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random
the probability
(a) The student is enrolled in mathematics=
(b) The student is enrolled in English.=
(c) The student is enrolled in both.=
(d) The student is enrolled in mathematics or English.=
(e) The student is enrolled in English but not in mathematics.
=
(f) The student is not enrolled in English or is enrolled in mathematics.
=
Answer:
y = 4.125x + 496.25
Step-by-step explanation:
Set the data up as points. Then deal with the points.
Givens
(30,620)
(70,785)
y2 = 785
y1 = 620
x2 = 70
x1 = 30
Formula
Slope = (y2 - y1) / (x2 - x1)
Solution
Slope = (785 - 620)/(70 - 30)
Slope = 165 / 40
Slope = 4.125
===================
Now you need the y intercept. Either one of the two given points will give you that.
y = 620
x = 30
m = 4.125
y = mx + b
620 = 4.125*30 + b
620 = 123.75 + b
620 - 123.75 + b
b = 496.25
