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yuradex [85]
3 years ago
13

How do I divide that problem

Mathematics
1 answer:
Mrrafil [7]3 years ago
7 0
First you would do 36/4 and get 9 then you would subtract the exponents 5-3 and the answer would be
    
9x to the second power
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Estimate 23,945 + 46,718 by rounding to the highest place value.
kolbaska11 [484]
The highest place value is in the ten thousand for both of these numbers. Let's round the two numbers first, and then we will add them. Let's round 23,945. So, we need to round to the ten thousand place, so we look at the number behind it (3) and act accordingly.
Remember:
5 or more? Raise the Score
4 or less? Let it Rest
We are looking at the bolded number: 23,945. This number is 4 or less, so we let it rest. So, the new rounded number is 20,000. 
Now let's look at 46,718. So, we need to round to the ten thousand place, so we look at the number behind it (6) and act accordingly. Look at the bolded number: 46,718. This number is 5 or more, so we raise the score. The new rounded number becomes 50,000.
Now, all you have to do is add 20,000+50,000, which is 70,000. Hope this helped!
4 0
3 years ago
A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups
HACTEHA [7]

Answer:  b. 8.56 to 21.44

Step-by-step explanation:

Let  \mu be the  mean number of pushups that can be done.

As per given , we have

Sample size : n= 10

Degree of freedom = n-1=9

Sample mean : \overline{x}=15

Sample standard deviation : s=9

Significance level : α=1-0.95=0.05

From t- distribution table ,

Critical two -tailed t-value for α=0.05 and df = 9 is

t_{\alpha/2, 9}=t_{0.025,9}=2.2622

Confidence interval for \mu is given by :-

\overline{x}\pm t*\dfrac{s}{\sqrt{n}}

=15\pm (2.2622)\dfrac{9}{\sqrt{10}}\\\\\approx 15\pm 6.44=(15-6.44,\ 15+6.44)\\\\=(8.56,\ 21.44)

Hence, the  95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.

5 0
3 years ago
2(2x) + 10 = 3x + 13<br><br> Please help
zlopas [31]

Answer:

x = 3

Step-by-step explanation:

:))

5 0
2 years ago
Read 2 more answers
Riaz wants to spend no more than $1,250 on his trip. The airfare is $439. Write and solve an inequality to find the maximum amou
Ilya [14]

Answer: \\ Let \:  x \:  be \:  the \:  amount  \: of  \: money  \: he \:  can \:  spend \\ We  \: have  \: an  \: inequality:x +439 \leqslant 1250 \\ \Leftrightarrow  x \leqslant 811 \\ So \:  the  \: maximum  \: amount \:  he \:  can \:  spend  \: is  \: \$ 811

4 0
2 years ago
Solve the inequality and graph the solution on the line 5x+7≤-8
bija089 [108]

Answer:

If my calculations are correct.

Step-by-step explanation:

3 0
2 years ago
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