Answer:
AFM = 140
LFM = 70
Step-by-step explanation:
Here, we are to calculate LFM and AFM
Since AFM was bisected, then LFM + AFL is AFM
and also AFL = LFM
Thus;
11x + 4 = 12x -2
12x-11x = 4 + 2
x = 6
AFM = AFL + LFM = 11x + 4 + 12x-2 = 23x + 2
Substitute x = 6
AFM = 23(6) + 2 = 140
LFM = 11x + 4 = 11(6) + 4 = 66 + 4 = 70
Answer:
TU = 6
Step-by-step explanation:
Using the Segment Addition Postulate, we know that TU + UV = TV, and since UV = 6 and TV = 12, we know that TU + 6 = 12, therefore, TU = 6.
Someone is writing the answer so ill just give you this tip for whenever.
A negitive times a negitive is positive
a negative times a positive is negitive
and a positive times a positive is positive (just had to add it to be complete)
The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original
If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
Since f(x) is up and down, simply decrease the overall equation by 2 to get 2sqrt(x+3)+3 instead of +5. To move it 5 to the right, we have to do something kind of weird, which is subtract 5 from (x+3) instead of add 5 to get
2sqrt(x-2)+3.
