The area in which the right angle was at before. the angle nor the triangle changes
Answer:
The running time is quadratic (O(n²) )
Step-by-step explanation:
For the set up, we have a constant running time of C. The, a log-linearsorting is called, thus, its execution time, denoted by T(n), is O(n*log(n)). Then, we call n times a linear iteration, with a running time of an+b, for certain constants a and b, thus, the running time of the algorithm is
C + T(n) + n*(a*n+b) = an²+bn + T + C
Since T(n) is O(n*log(n)) and n² is asymptotically bigger than n*log(n), then the running time of the algorith is quadratic, therefore, it is O(n²).
Answer:
The answer is B.
Step-by-step explanation:
Answer:
33.6
Step-by-step explanation:
this is a circle
so
the area of a circle = pi x radius squared(since it's a 2-D shape)
but this is 3-D
so
V = 2664.31 = (4/3)(
)
you could also use
A = ³√(36 * π * V²) when A is the surface area
but those are too long, so let us just use the answer choices
V = 3.14 x answer choice x radius sqaured
V = 3.14 x 8.6 x radius sqaured
2664.31 = 3.14 x 8.6 x radius sqaured
radius sqaured = 2664.31/3.14 x 8.6
radius sqaured = 2664.31/27.004
radius sqaured can't be made with this
lets skip V
radius sqaured = 2664.31/3.14 x 17.2
radius sqaured = 2664.31/54.008
since 27.004 didn't work, and 54.008 is 2 times as that
radius sqaured = 2664.31/3,14 x 33.6
radius sqaured = 2664.31/105.504 ≈ 25
25 square rooted is 5
so
33.6
So first we calculate the weekly hours:
23.80 x 34 = 809.20
Then we calculate the time and half:
23.80 x 6 x 1.5 = 214.2
Then we total then together:
214.2 + 809.20 = 1023.40