at a basketball game the home team scores 60% of the points the home team scores 45 points how many points are scored in all

The amount of toothpaste in a tube is normally distributed with a mean of 6.5 ounces and a standard

Anarel [89]

Answer:

a) 266 tubes , TC_r = $53.2

b) 266 tubes , T.Loss = $13.30

Step-by-step explanation:

Given:

- The sample size of tubes n = 1,000 tubes

- The mean of the sample u = 6.5 oz

- The standard deviation of the sample s.d = 0.8 oz

- Cost of manufacturing a tube C_t = 50 cents

- Cost of refilling a tube C_r = 20 cents

- Profit loss per tube Loss = 5 cents

Find:

a). How many tubes will be found to contain less than 6 ounces? In that case, what will be the total cost of the refill?

b) How many tubes will be found to contain more than 7 ounces? In that case, what will be the amount of profit lost?

Solution:

- First we will compute the probability of tube containing less than 6 oz.

- Declaring X : The amount of toothpaste.

Where, X ~ N ( 6.5 , 0.8 )

- We need to compute P ( X < 6 oz )?

Compute the Z-score value:

P ( X < 6 oz ) = P ( Z < (6 - 6.5) / 0.8 ) = P ( Z < -0.625 )

Use the Z table to find the probability:

P ( X < 6 oz ) = P ( Z < -0.625 ) = 0.266

- The probability that it lies below 6 ounces. The total sample size is n = 1000.

The number of tubes with X < 6 ounces = 1000* P ( X < 6 oz )

= 1000*0.266 = 266 tubes.

- The total cost of refill:

TC_r = C_f*(number of tubes with X < 6)

TC_r = 20*266 = 5320 cents = $53.2

- We need to compute P ( X > 7 oz )?

Compute the Z-score value:

P ( X > 7 oz ) = P ( Z > (7 - 6.5) / 0.8 ) = P ( Z < 0.625 )

Use the Z table to find the probability:

P ( X > 7 oz ) = P ( Z > 0.625 ) = 0.266

- The probability that it lies above 7 ounces. The total sample size is n = 1000.

The number of tubes with X > 7 ounces = 1000* P ( X > 7 oz )

= 1000*0.266 = 266 tubes.

- The total cost of refill:

T.Loss = Loss*(number of tubes with X > 7)

T.Loss = 5*266 = 1330 cents = $13.30

5 0

3 years ago

Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th

Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0

3 years ago

Solve log (x + 1) = –x2 + 10 by graphing

Anit [1.1K]

Your answer would be x = 3.0645

CHECK
log (3.0645 + 1) ?=? -(3.0645)2 + 10
log 4.0645 ?=? -9.3912 + 10
0.609 ?=? 0.609

Hope this helps!

So in short your answer is x = 3.0645

3 0

3 years ago

Read 2 more answers

Which undefined term is needed to define a circle?<br> O Point<br> O Radius<br> O Line<br> O Ray

Sever21 [200]

Answer:

I think the answer is option B radius

Step-by-step explanation:

hope it helps.

good day ✌️

6 0

3 years ago

Which expression represents the lateral surface area of the cone?

Brrunno [24]

Answer:

Option "3" is the correct answer to the following question:

Step-by-step explanation:

Given:

Radius of cone (r) = 6 centimeter

height of cone (h) = 8 centimeter

slant height of cone (l) = 10 centimeter

Find:

Lateral surface area of the cone = ?

Computation:

⇒ Lateral surface area of the cone = $\pi$ rl

⇒ Lateral surface area of the cone = $\pi$ (6 centimeters) (10 centimeters)

⇒ Therefore, option "3" is the correct answer.

3 0

3 years ago